Recent content by Woopa
-
W
B Newton's second law -- rockets
I am having difficulty understanding the information below. In the second line it states that F=0 as there is no external force on the system. However it later calculates acceleration of the rocket. How can Force=0 if there is acceleration? (This is the first time I have encountered the... -
W
How Do You Derive Electron Energy in Physics Equations?
I am having trouble understanding this derivation and need some guidance. 1) I tried solving the algebra from the first equation to the second equation circled in red. Can someone please help with what algebra steps, I cannot solve to the circled solution. 2) What does Ee stand for? Is it...- Woopa
- Thread
- Derivation Electron Energy
- Replies: 3
- Forum: Introductory Physics Homework Help
-
W
Determine how much energy the alpha particle carries
Thanks for the clarification everyone!- Woopa
- Post #15
- Forum: Introductory Physics Homework Help
-
W
Determine how much energy the alpha particle carries
Okay I think I've got it! So energy of alpha particle 2(1.0073x931.55)+2(1.0087x931.55)=3756MeV Total energy = 88x(1.0073x931.55)=138(1.0087x931.55)=212247Mev Ratio total energy:alpha particle = 212247/3756=56 So the alpha particle makes up 1/56th of the total energy. Why do we only think...- Woopa
- Post #5
- Forum: Introductory Physics Homework Help
-
W
Determine how much energy the alpha particle carries
the relative energy would be the ratio of 4: 222= 0.018?- Woopa
- Post #3
- Forum: Introductory Physics Homework Help
-
W
Determine how much energy the alpha particle carries
I can follow through all of this worked example until the final step 55/56x4.84= 4.75MeV Where does the 56 come from?- Woopa
- Thread
- Alpha Alpha particle Energy Particle
- Replies: 14
- Forum: Introductory Physics Homework Help
-
W
Ideal gas law- Find the pressure
Where is my mistake?- Woopa
- Post #7
- Forum: Introductory Physics Homework Help
-
W
Ideal gas law- Find the pressure
Ah yes that make sense I can see now the numbers are actually for V, the way they've written out the equation has confused me. However I am still arriving at the final answer P=2P. I must be making a mistake in my algebra. I will post my working in a moment- Woopa
- Post #6
- Forum: Introductory Physics Homework Help
-
W
Ideal gas law- Find the pressure
Do you mean it is a typo/ error in the worked solution?- Woopa
- Post #4
- Forum: Introductory Physics Homework Help
-
W
Ideal gas law- Find the pressure
Question: Answer: In the third last line of working, I do not understand why the pressure variable is changing? Shouldn't pressure remain constant and only the Volume change?- Woopa
- Thread
- Gas Gas law Ideal gas Ideal gas law Law Pressure
- Replies: 8
- Forum: Introductory Physics Homework Help
-
W
Understanding the Force of Two Cubes
The solution is : The pressure inside the solid is zero and outside it equals atmospheric pressure, 1.01 × 10^5 Pa. Thus, the force is given by: F =pA = 1.01 × 10^5 × (0.25)^2 = 6.3 × 10^3 N I do not understand why only the area of one cube is used in the solution, should it not be the area...- Woopa
- Thread
- Force
- Replies: 1
- Forum: Introductory Physics Homework Help
-
W
Thermal Physics Problem -- Dropping a hot mass of iron into 20C water
Excellent I've got it! Thank you!- Woopa
- Post #4
- Forum: Introductory Physics Homework Help
-
W
Thermal Physics Problem -- Dropping a hot mass of iron into 20C water
Hi, The solution for this question is thermal energy lost= thermal energy gained 0.200x450x(300-T)=1.0x4200x(T-20) T=26 degrees celcius. However, I am struggling to grasp why (300-T) is used. I have always known a change in something to be final - initial. Therefore change in T= Final-...- Woopa
- Thread
- Hot Iron Mass Physics Thermal Thermal physics Water
- Replies: 4
- Forum: Introductory Physics Homework Help
-
W
Mechanical energy- how to solve for v
It's just clicked! Thank you for the prompts I've got it- Woopa
- Post #7
- Forum: Introductory Physics Homework Help
-
W
Mechanical energy- how to solve for v
If I multiply by 2 and then sqrt I end up with VA=√ v^2-gh I'm just missing the 2gh- Woopa
- Post #5
- Forum: Introductory Physics Homework Help