Recent content by wsabol

Hey guys, first post. I'm trying to determine to the rate at which liquids drop out of a gas pipeline. I've modeled the system in a chemical process program, but its only a steady state model. Anyways, here's some of what I can get out of that program: Heat of vaporization Total Heat Transfer...

Damn you got me. Ok.

1 is a real whole number. 0.999... is a limit. That limit is equal to 1, not the real decimal number 0.9999...(as close as you can get to infinity without getting there, because the infinite term of the sequence ever happen)...9

I get it. 0.9999... is just short hand for a limit. It isn't a real number in the traditional sense.

I feel like you just made my point... The infinite term simply does not occur, therefore, is will always be 0.999999...9 which is not equal to one. The limit equaling one is exactly that, a limit. 0 is not a member of the set of values in the sequence 9/10^n for n[1,Inf). This sequence is...

I agree, but infinity isn't a real number. Therefore for 9/10^∞ isn't real. Just like saying the function y = 1/x is never equal zero. Is is "at" infinity, but where is infinity? its not real, so zero is not part of the set of values for y. In my mind comparing 0.9999... and 1 is apples to...

Which 2 dimensions do you mean? The two horizontal directions? or horizontal and vertical? If its the 2 horizontal directions, I'd suggest doing the problem in polar coordinates, so it simplifies back to a 1D problem :) For the vertical component, there is NOT a continuous numerical...

Yes, I know that. But specifically for root locus problems, I don't recall using those equations. I doubt his prof will require a FULL derivation of simple harmonic motion from the EOMs. I think the presumption that A*ejwt + B*e-jwt equals C*sin(wt) + D*cos(wt) is pretty standard. You...

The first thing I thought of when I read the post actually will fit this pretty well. I'm not sure of the techinal name, but its a centrifugal pump, but in reverse. You have an impeller on the end of your shaft that you want spun. Then just as you said you can force air into the impeller...

P = T*w ?

Well, the driving force for a wrench isn't purely lateral. You could get away with it for very short distances, but there will be motion in two directions rather than just one. A wrench isn't incorrect per se, but the crank slider is a more correct.

Maybe root locus. I know that is in the imaginary plane, but I don't ever remember using those equtions, althought its entirely possible to do so.