Recent content by Xaras

Nobody has an idea ? :)

There is something that I don't get, we're in low frequency. So Xc -> infinite = > Zc = 0 right ? So it means that Vr(w) = E(w) ?

Let's do it again. Here the goal is to compute the voltage across the resistor. So : Vr(w) = R1 * E(w) / (R1 + ZC1) = R1 * E(w) / ( R1 + 1/jC1w) = (E*R1*C1*jw)/(1+ jR1C1w).

Yes sure, So here are the answers for the cut off frequency = 1/(2*pi*R*C) = 2653 kHz. For the Vr(w) = 10000/(1+ 2.26*10^(-5)*j). Is it right ?

By the way I forgot to put the numbers on the picture, here they are ...

I didn't get what you wanted to say ...

Problem Statement: Questions about motors (practical tests) Relevant Equations: synchronous/induction motors Hey guys, Some practical questions about motors :) Let's admit I have to test one stator winding phase (in high voltage, we test one at the time). During this test what do you do...

I was just hesitating because I thought current was flowing to the system and to the PD pulse counter so we can't apply the theorem. But thanks for your answer :) !

Problem Statement: Computing AC voltage Relevant Equations: cut off frequency, ac voltage. Hey guys, Amazing to be in this group ! Please find attached the diagram of the problem. E = 10kV at 60Hz, C1 = 60pF and R1 = 1k. I have to compute the ac voltage in reference to ground at point [1]...