Recent content by xmflea

Why conceptually, does the ground state for the particle in the box model correspond to n=1 while for the harmonic oscillator and the particle on a ring model it is n=0? For all three models, why don't we consider negative quantum numbers? attempt:...the particle in a box and particle on...

Calculate the change in energy when the following transition occurs in the hydrogen atom. n = 4 ----> n = 1 equation E = -Rh/n^2 eventually my answer is 2.04E-18J because my book tells me to take 1 over n(low) squared minus 1over n(high) squared and multiply by rydberg constant.. so...

see what i could do...is since i know volume of a sphere is 4/3r^3pi, i can just say that the radius is 3, and get 36pi x 9. to get 324pi. but I am sure my teacher would expect me to do some actual integration.

Evaluate the flux integral using the Divergence Theorem if F(x,y,z)=2xi+3yj+4zk and S is the sphere x^2+y^2+z^2=9 answer is 324pi so far i took the partial derivitavs of i j k for x y z and added them to get 9. so i have the triple integral of 9 dzdxdy i think u have to use polar...

Evaluate the line integral of f(x,y) = x+2y along C, where C is the path counterclockwise around the upper half of the unit circle Attempt: parametric r(t)= cos(t)i + sin(t)j 0<t<pi ds=root(1)dt integrate from 0 to pi the function cost + 2sint, and i get -2. correct answer is 4. i...

Let C be the triangle in the plane from (0,0) to (1,1) to (0,1) back to (0,0). evaluate the line integral of f along C if f(x,y)=(x+2y). attempt: C1: x=t y=t ds=root(1)dt, integrated t+2t from 0 to 1 to get 3/2 C2: x=-t ds=root(1)dt, integrated -t from -1 to 0 to get 1/2 C3: y=-t...

OH! ok i get it! ok by the way, so everytime i look for the bounds, do i do the same thing as i did with this problem? just find t where x begins, and where x ends? can i do it with y or z?

i got it from the function x + y^2 -2z. just substituted the variables with t like my book says to do.

ok. i re did my math and now I am getting an even worse answer. so integrating the function (t + t^2 -2t) i get (t^2/2) + (t^3/3) - (t^2). and plugging in from 0 to 1 i get...1/2 + 1/3 -1. common denominator is 6, so 3/6 + 2/6 - 6/6 and i get -1/6, so now my answer is root(14) times -1/6

well, it just tells me that at the start... t=0 since x=t.. and at the end. if x=1, then t=1 as well. which means the bounds are 0 to 1, which is how i got my answer (11/3) times root(14), but the key says (11/2) times root(14) instead..maybe the answer key is wrong?

so do i set x=y=z to get t=3t=-2t?

the reason why i thought it was from 0 to 1 to begin with is because i did this... -t+t^2. convert to t(t-1), t = 0, t=1

sigh, to be honest.. somehow I've made it this far in calculus without ever knowing how to set up bounds for definite integrals whenever they are not given. i can solve them when the bounds are given, but when their not. I am screwed. anyways, i don't expect anyone to straight up tell me what...

starts at 0, ends at 3?

Let C be the line segment from (0,0,0) to the point (1,3,-2). evualuate the line integral of f along C if f(x,y) = (x + y^2 -2z) so far i was able to write the parametric form x = t y=3t and z=-2t the square root of all the derivatives is root(14). so i get root(14) times integral of...