Recent content by xwhyy

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Thank you for your reply! so: V = Q / [4*pi*epsilon*r1] Q = V * 4* pi * epsilon * r1 V_connected = (V * 4 * pi * epsilon * r1) / ( 4 *pi * epsilon * 2 * r1) which after simplification is equal V_connected = V/2 is that true? :)

Hi, again very simple problem Homework Statement Metal sphere of radius R1 is charged to 10V. It is then connected to another sphere with R2 = 2*R1. What is the final potential? Homework Equations The Attempt at a Solution V = E * distance so in the case of disconnected...

yes, that's the case. Thank you guys! :)

Hi, I have a problem with this basic question since it's been a while with my last time with physics :) Homework Statement I'm given 2 charges q1=-e and q2=e, attracting each other with force F12 within a distance r12What would be the force F13 between q1 and q3 = 2e on the distance r13 =...