Recent content by yb1013

okay thank you very much!

1. Homework Statement Two point charges q1 = -5.60 nC, and q2 = -14.0 nC are separated by 25.0 cm (see figure below). http://www.webassign.net/yf12/21-p-031-alt.gif (a) Find the net electric field these charges produce at point A magnitude 10360 N/C direction is to the right (b)...

I'm still not quite sure where you're going with that. I tried a couple things but I ended with the wrong answer..

Homework Statement Two point charges q1 = -5.60 nC, and q2 = -14.0 nC are separated by 25.0 cm (see figure below). http://www.webassign.net/yf12/21-p-031-alt.gif (a) Find the net electric field these charges produce at point A magnitude 10360 N/C direction is to the right (b)...

Homework Statement A ring-shaped conductor with radius a = 2.20 cm has a total positive charge Q = +0.145 nC uniformly distributed around it, as shown in the figure below. The center of the ring is at the origin of coordinates O. (a) What is the electric field (magnitude and direction) at...

never mind, I figured it out

Homework Statement Assume that Young's Modulus for bone is 1.50 X 10^10 N/m2 and that the bone will fracture if more than 1.50 X 10^8 N/m2 is exerted. (a) What is the maximum force that can be exerted on the femur bone in the leg if it has a minimum effective diameter of 2.60 cm? (b)...

well its right, I stated in one of my other posts that the numbers were exactly what my actual problem contained. the 720 N of the bear is actually 740, which is why when I added all the numbers up I got 1020 instead of 1000.. So in the end the force is equal to 720 Sorry for all the confusion

Yea forget what I just said, I had a brain fart for a second there lol Its just 720, sorry about the confusion. Thanks again!

Ok well the numbers in that question aren't actually my exact numbers, but with my numbers I come out with: Rsin(theta) = 720.65 would that mean that its: Rsin(60) = 720.65 R = 832.13 So 832.13 would be the force in the y-component?? I only have one more guess left on my homework...

So would it go like 345.66cos(60) - 1020 = 0 ??

would this be closer to the y-component for the force? Rsin(theta) = 720 + 200 + 80 - 345.66sin(60)

o I am sorry that's what I forgot, http://www.webassign.net/pse/p12-42.gif thats the picture

Homework Statement A hungry bear weighing 720 N walks out on a beam in an attempt to retrieve a basket of food hanging at the end of the beam. The beam is uniform, weighs 200 N, and is 5.40 m long; the basket weighs 80.0 N. a) When the bear is at x = 1.00 m, find the tension in the wire and...

oo ok, thank you