Recent content by Yohanna

Here is the full answer, as I said before.. An open cylinder of height 5ft and cross sectional area of 1 ft2 is initially empty. There is a small hole at the bottom of the cylinder with an area of 0.005 ft2. Water is drawn into the tank at a rate of 4.8ft3/min. At the same time water is...

This is also give me inspiration how to do this, of course don't need to be sorry for telling my mistake, thank you for that, I really mean it. Now I just need to solve the integral, I am close to see the answer. I will post again here once I get it, thank you so much ! :):):)

Thank you for your inspiration again :) , yup i made mistakes and tried to redo it again. I recalculate as : cross sectional area of 1 ft2 = B area of hole 0.005 ft2 = A g = 32.17 ft/sec2 velocity in = 4.8 ft3/min = 0.08 ft3/sec velocity out = α√2gh ; α = 0.6 (source : J.C Borda, based on Edwin...

Thank you for your hint. I calculate the time to reach height of 1 foot is 12.5 second if there is no hole, then if there is a hole, it will takes longer time to reach that height. It proof my answer 0.21 second is wrong. here is my detailed calculation : cross sectional area of 1 ft2 = B area...

Homework Statement An open cylinder of height 5ft and cross sectional area of 1 ft2 is initially empty. There is a small hole at the bottom of the cylinder with an area of 0.005 ft2. Water is drawn into the tank at a rate of 4.8ft3/min. At the same time water is discharged out of the...