Recent content by Yousufshad

Homework Statement http://i41.photobucket.com/albums/e271/FireFox988/l10g10.gif The blocks shown in the figure below are connected by a string of negligible mass passing over a pulley of radius r = 0.250 meter and moment of inertia I. The block on the frictionless incline is moving up with a...

Ok, thanks, great to know :)

Homework Statement A motorist drives along a straight road at a constant speed of 14.4m/s. Just as she passes a parked motorcycle police officer, the officer starts to accelerate at 1.8m/s^2 to overtake her. Assuming the officer maintains this acceleration, determine the time it takes the...

Yeah sorry, I got it eventually, that was a tough question.

yes unfortunatly I am not understanding this, thanks for the help though ! :)

Okay, and now I am confused on how you figured out that md = mvt = MVt = MD how do i know this is true? Where would i be able to pull this formula from?

Whats confusing me is we started from Jennifer (mass 60.0kg) is standing at the left end of a 14.0m long 538.0kg cart that has frictionless wheels and rolls on a frictionless track. Initially both Jennifer and the cart are at rest. Suddenly, Jennifer starts running along the cart at a speed of...

There's too many equations being thrown around I'm getting very lost, how could I even relate m to v and M to V throuhg d/v = D/V

I'm not 100% sure but is it d/v = D/V ?

Okay mv=MV This is conservation of momentum, I know m= 60 M = 538 I only have one equation here trying to poke at two unknowns is there another formula I can pull out somewhere using v=5.1m/s relative to the ground?

Yeah, I believe i used that here earlier to calculate the speed of the cart with the given speed of jennifer " Pi = 0 so 60*5.1 = 538v v=0.568m/s velocity of cart"

Well since the net momentum is 0 and she increases her speed the speed of the cart would increase to cancel the momentum change Since we are talking about distances traveled relative to the ground her speed relative to the carts are irrelevant. Proof: Using her speed of 5.1m/s relative to the...

I would think so, no? If she travels slower the cart would also travel slower, so I guess not then? How could I implement this mathematically I feel a bit stuck here.

Ok so relative to the ground she is traveling at 5.1m/s - 0.568m/s = 4.523m/s 4.532m/s * 2.46s = 11.148m This is also an incorrect answer. I looked over my math and it all looks good, am I missing anything to consider?

Homework Statement Jennifer (mass 60.0kg) is standing at the left end of a 14.0m long 538.0kg cart that has frictionless wheels and rolls on a frictionless track. Initially both Jennifer and the cart are at rest. Suddenly, Jennifer starts running along the cart at a speed of 5.10m/s relative to...