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Rotational energy on an incline
so M is the mass of the moving system, which means M is 1.5 + 4(0.3) = 2.7 Kg V = √(2*2.7*9.8*1.2)/(2.7 + 0.006/0.1^2) V = √(63.504)/(3.3) V = 4.38 m/s And for part b I think you should see the diagram for better understanding- ZachAW
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- Forum: Introductory Physics Homework Help
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Z
Rotational energy on an incline
Homework Statement A cart whose body has mass M = 1.5 kg is set on four tires each of which has mass m = 0.3 kg and radius r = 0.1 meters. Each tire can be treated as a solid disk with rotational inertia mr2/2. The cart is set on an incline a height h = 1.2 meters high and released. At the...- ZachAW
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- Energy Incline Intro to physics Rotational Rotational energy
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- Forum: Introductory Physics Homework Help