Recent content by Zaurus21

I made an arithmetic error. Nevermind.

When finding lim(x->1) (1+2ln(x))^(1/(x-1)) = 1^(infinity) I let y = (1+2ln(x))^(1/(x-1)) then ln both sides giving ln(y) = ln(1+2ln(x)))/(x-1) Taking the limit of ln(y) gives 1/0, which is indeterminate and hence the limit does not exist. However, I typed this into MS Mathematics and got...