When finding lim(x->1) (1+2ln(x))^(1/(x-1)) = 1^(infinity) I let(adsbygoogle = window.adsbygoogle || []).push({});

y = (1+2ln(x))^(1/(x-1)) then ln both sides giving

ln(y) = ln(1+2ln(x)))/(x-1)

Taking the limit of ln(y) gives 1/0, which is indeterminate and hence the limit does not exist.

However, I typed this into MS Mathematics and got the limit as e^2.

Help please.

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# Indeterminate limit of the form 1/0

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