Recent content by zbtzylong

I just don't feel like I'm wrapping my head about this correctly. Using your K=qV formula, I worked the other way around. K=1/2mv^2 Thus, 1/2mv^2 = qV V = (mv^2)/(2q) Using this, I still didn't get the correct answer.

Homework Statement Through what potential difference would an electron need to be accelerated for it to achieve a speed of 46.0% of the speed of light, starting from rest? The speed of light is c= 3.00 x 10^8 m/s m_e = 9.11 x 10^-31 kg |e| = 1.60 x 10^-19 C Round your answer to three...