I just don't feel like I'm wrapping my head about this correctly.
Using your K=qV formula, I worked the other way around.
K=1/2mv^2
Thus,
1/2mv^2 = qV
V = (mv^2)/(2q)
Using this, I still didn't get the correct answer.
Homework Statement
Through what potential difference would an electron need to be accelerated for it to achieve a speed of 46.0% of the speed of light, starting from rest? The speed of light is
c= 3.00 x 10^8 m/s
m_e = 9.11 x 10^-31 kg
|e| = 1.60 x 10^-19 C
Round your answer to three...