Care to clarify?
IS not HP = Torque x 2∏r x RPM/33000
OR HP= T x RPM/5252
So HP is useless really. That is why I didn't really want to use a power equation because it is simply a factor of Torque anyways. Without having torque you can't have HP numbers. IT's just a fictitional way to explain...
Yes sorry sine of 1 as in the conrod angle of 90 degrees(not radians) to the axis of rotation. The length of the lever arm being 3" from the point of axis, to the point of force. Altogether, the "moment arm". So at 30 degrees(Sine of 0.5) the moment arm acts as a 1.5" lever arm. It's easier for...
Ok, I just couldn't imagine how if two torques were at the same magnitude how it would become a SUM on the final drive gearing. I suppose I was confusing MASS with FORCE. Like if you weigh yourself one foot at at time and you were balanced, both scales will only show 1/2 your true weight.
I...
It should be clear to what I'm comparing with as I've explained it above.
Comparing a dual crank design, to a single crank that has a piston surface of the same diameter, with a moment arm the same length(3"). The only difference(minus added friction/etc) is there are now two pistons acting...
This is simply from googling. It's simple really, there are many engines like this in use by the navy. What I'm trying to understand, is by adding another crank that is run by the same gas pressure in the same cylinder adding to the total torque? So imagine those two cranks are geared so they...
I have been boggled by something for a while now. It pertains to the forces acting on two cranks in an opposing piston engine.
So let's just assume the pressure remains constant in the cylinder(for simplification). Now half way through the cycle one piston is acting on a 3" moment arm with a...