Recent content by Zeynaz

I know that the answer is NO because now there is an extra substance (the fluorescent powder) that is affecting the emission. However, i don't know how fluorescent powder works in this case. I tried to search it up and only found that Fluorescent powder will 'fluoresce' when it absorbs UV...

alright, thanks!

yes you were right i made a mistake with my calculations. then in this case my only question would be; would it be possible to say that E(n)= PE+KE= hf?

oh right i used m as the electron but i had to use the mass of the ball. this gives me v= 5.37e-14 m/s which is still not the correct answer. Also, if the potential is 0 inside the box, E=KE.

I am having difficulties understanding this concept. Particle in a box (as far as i understood) shows that the electrons or particles need a certain about of potential energy to escape the one-dimensional potential well. I think its pretty similar to the concept of the electons and ionising...

I am struggling to answer questions about gasses. In this case the only way i can think of is, it has to do with the change in atmosphere right? because if we think about the formula P/T=P/T as the temperature decreases the pressure should increase. But in this case we have a smaller pressure...

yes, because when i do that and divide the value i got by 13 i get 31m2. which is the correct answer. Thank you!

if i divide it like that then i would get Joules/ s^2 * 1hour^2 which not what i want. so the h in there equals to the number of hours in 1 year? because if i multiply wh with 3600s/1h i would get joules. So to be able to get W only, i would have to divide 3500 kwh by the number of hours in 1 year??

to be able to get W from Wh (or Joules), i should divide 3500 kWh by 3600 right? so i get 972 W or (joules per second is used by the house) since the solar panel produces 13 W per m2 i divide the watts needed by watts produced 971w/13w = 74 m2 the correct answer is 31 m2

First, I calculated the power generated by the solar panel in one day. So since the intensity is 1.0e3 watts per 1 m2. 10% of this peak power is utilized so (1000)(0.10)=P-utilized=100W (per 1 m2) the solar panel has the efficiency of 13% so of this power only 13% is useful. P-useful=...

I tried it like that but it didnt work out. i found the loss of heat per hour for both the body and the environment. and i added these together (because loss of heat of human plus the environment). Because my answer was wrong i tried to subtract these values but still not correct. The correct...

Ohh i see. I had to multiply it by 60

This question is in a unit about emission and absorption, Atomic Physics So far, I calculated the Power that the person gives off which is by using the S-B law formula. P= (s-b constant)*1.8*305K^4= 883 W (or Joules per second) for the ambient i used the same formula and found P= 702 W I...

Alright! thanks

So far what i figured out is that R2 and R3 are in parallel, R1 and LDR in parallel. And these two parallel circuits are parallel to each other ( tell me if I am wrong) The voltmeter has to read 0 but I am not sure how i can achieve that. Is there a rule where when the resistance of each side...