Recent content by ZhangBUPT

Thank you very much! And I'll figure it out.

Thanks for your answer. I can derive the second equantion using your transformation. But in both expressions, a and a^{\dagger} are annihilation and creation operators, respectively, and they are real. Is the transformation still valid?

Hi, I have a question about two different expressions of Jaynes-Cummings Hamiltonian H=\Delta_c a^{\dagger}a+\Delta_a \sigma_{+} \sigma_{-} + g (a^{\dagger}\sigma_{-} +a\sigma_{+} ) and H=\Delta_c a^{\dagger}a+\Delta_a \sigma_{+} \sigma_{-} +i g (a^{\dagger}\sigma_{-} -a\sigma_{+}...