Recent content by zileas

I don't understand how these help me... isn't there still 2 unknowns with a and t ? I'm so confused.

Homework Statement A soccer ball is kicked with an inital speed of 12.0 m/s in a direction of 25.0 degrees above the horizontal. Find the magnitude and direction of its velocity A) 0.250 s and b) 0.500 s after being kicked. C) Is the ball at its greatest height before or after 0.500 s...

The horizontal aspect I think is fairly straightforward, using VH = d / t; VH = 17.8 m / 2.24 s for 7.95 m/s ... I am still lost on finding the initial vertical(y) velocity however..

I have: 2.24 s = (delta)V / a 2.24 s = (delta)V / -9.80 m/s2 (2.24 s)(-9.80 m/s2) = (delta)V (delta)V = -22 m/s Vi = 11 m/s ; but I am not sure of anyyy of this :(

I have been trying to split it up into its horizontal and vertical motions, using some equations like Vf = (Vi)2a(delta)d and d = (Vi)t + 1/2at2 but to be honest I'm not too sure what I'm doing with them... just seems to be too many unknowns, and I'm not particularly strong in trig.

Homework Statement I know this is a basic question but this is my first physics course ever and I am having big time trouble, any help is appreciated! Chipping from the rough, a golfer sends the ball over a 3.00 m high tree that is 14.0 m away. The ball lands at the same level from which...