It has been several years since I have dealt with fluid mechanics. I have a 4hp pump that circulates the water in a 4ft swimming pool. A 2in pipe is connected to the outlet which runs up about 1ft. It passes through a shutoff valve and is then split into two streams, both 2in pipe, by a...
What equation(s) do I use to calculate the weight necessary to crush a pipe lying horizontally on the ground and the point at which the initial deformation occurs. What is the name of this property? I'd like to compare my findings with a manufacturer's specs.
I have a 3000 lb weight resting...
Fluid Dynamics Question:
I have a 1.5" pipe that has water pumped through it. The pipe is immediately split by a manifold into 5 separate 0.75" pipes after exiting the pump. Each 0.75" pipe runs to an outlet at varying lengths from the manifold (15", 37", 52", 89", and 126"). I want to know...
Sorry for the wait. I had been searching for that data, but came up empty handed so I tried calculating it myself. I tested the vinyl material with a Tinius Olsen Tensile Machine and came up with the following values. The material is stronger in the machine direction than it is across the width...
If I understand that equation correctly, then it finds the force that is perpendicular to the plane it is acting on. You are correct that this would produce the horizontal force on the vertical wall of the pool. But once you reach the rounded portion of the pool wall, the hydrostatic force is no...
What did it accomplish? Not a darn thing. I had forgotten that forces act uniformly across an object so I wasn't sure how to combine the forces.
I used the equation F = 0.5*(rho)*g*(H2^2 - H1^2)/cos(theta) to calculate the hydrostatic forces acting on the pool wall, where
(rho) = density
g...
I am trying to calculate the stress applied to a 1' x 2' piece of vinyl. The vinyl is welded to the bottom of an above ground pool and is used to hold the leg support, which holds up the side of the pool, in place. There is a leg support every 4'. A picture of the pool can be found at...