Recent content by zygi

right. you can look "Computation and Quantum ınformation " Authors: Micheal A. Nielsen and Isaac L. Chuang ... in this book you can find answer of your question... see you..

To be honest, yes :) , Usually we deal with maths. What do you mean "|+><+|+|-><-| is not a state (it can be but it isn't here) " I not quite understand.

Thanks, for your comment. İt is really diffucult. it will be Lots of interaction potential in the perturbation term. İndeed, each of electron are identical. But in this time How will write the distances?

|+><+|+|-><-| state that you said is mixed state. Because, You can constitue infinite in different style. So we don't know anything about previous case. For example, "Poincare-Block sphere " (we saw it in the lecture) There is a sphere in our hand. İts outside(in other words its shell)...

Hi macduy, I guess, I understand this time. For example, |S_x;+>= 1/Sqrt(2)(|+>+|->) is |S_x;+> mixed state? This is your question. I think, |S_x;+> still is pure state. Now, I asked you. How do we know whether pure or mixed of any state. As far as I know, it related to density matrix...

Exactly I didn't understand your question. But I can say those. in Pure states be zero entropy, in Mixed states be " LnN" ; N: dimensionality; then if N increase, entropy increase too . . .

We can apply perturbation to Helium. ıt has two electrons. But Mercury has lots of electrons. in this case, can we apply perturbation to Mercury? How?

Hi, G15 You look " Modern Quantum Mechanics J.J Sakurai " Chapter 3 First section rotations in IR^3