Polynomials do or don't have integer roots?

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Homework Help Overview

The discussion revolves around determining whether a polynomial has integer roots, specifically focusing on methods applicable to polynomials with integer coefficients. Participants explore various approaches and theorems related to this topic.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss methods such as polynomial division, Horner's Method, and the Rational Root Theorem. Questions arise regarding the applicability of these methods to polynomials with integer coefficients and the general case of real polynomials. Eisenstein's criterion is mentioned as a potential tool for polynomials with integer coefficients.

Discussion Status

Guidance has been offered regarding the use of Eisenstein's criterion and the Rational Root Theorem. Participants are actively questioning the assumptions about the coefficients of the polynomial and exploring the implications of those assumptions on the existence of integer roots.

Contextual Notes

It is noted that the coefficients of the polynomial in question are odd integers, which may influence the nature of the roots. Some participants express a desire for more information about the polynomial's coefficients to better assess the situation.

povatix
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Homework Statement



Is it there a method to find out if a polynomial has no integer roots?


The Attempt at a Solution


I tried the division of polynomials, as well as the Horner's Method, but no luck.
 
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povatix said:

Homework Statement



Is it there a method to find out if a polynomial has no integer roots?


The Attempt at a Solution


I tried the division of polynomials, as well as the Horner's Method, but no luck.

Use "rational root theorem".
 
Doesn't the rational root theorem only apply to polynomials over the rationals?
 
Yes, basically. Is there a method for general real polynomials?
 
Povatix,

Does the polynomial itself have integer coefficients? If so, you can use Eisenstein's criterion.
 
abelian jeff said:
Povatix,

Does the polynomial itself have integer coefficients? If so, you can use Eisenstein's criterion.

Irreducible is sufficient to show there is no rational root, but it's not necessary. Kummer was right. Just check all the possible rational roots, if none are integers, then there are none. The OP's polynomial almost certainly has rational coefficients. And if it doesn't I wish they had displayed it.
 
Here's the equation.

\chi^{10} + p\chi^{9} - q\chi^{7} + r\chi^{4} - s = 0

thnx in advance
 
If the coefficients are all integers, then the only possible integer solutions are s or its factors. The only way I know of determining whether any of those ARE solutions is to try them in the equation. Are you doing this for specific values of p, q, r, s? Obviously, the equation you give will have integer values for some values of p, q, r, s and not for others.
 
Oh right, sorry, the question also states that p q r and s are all odd integers
 
  • #10
If x is an odd integer, then so is any power of it and so is any odd integer times any power. What can you say about the sum (or difference) of 5 odd integers?

If x is an even integer, then so is any power of it and so is any integer times any power. What can you say about the sum (or difference) of 4 even integers. In order that the value of the polynomial be 0, what must s be?

It would have helped a lot if you had given us all this information to begin with!
 
  • #12
Yes, it's true. This is part of a much larger enrichment program aimed at the top students in Year 10, which includes a textbook that is meant to aid you through the 16 questions.

P.S. How did you find out?
 
  • #13
I'm Psychic =]

Jokes, I did it this year too. You will like that thread then, it has a lot of other questions from the program :)
 

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