An iron rod has a diameter of 2.50cm at 20.0°. To what temperature must it be heated to fit into a ring with an inside diameter of 2.51cm. I'm given: alpha=1.0x10^-5
I'm not sure how to apply it to the △L=(alpha)(object length)△T
A 215.m steel bridge has an expansion joint of 18.0cm at one end at -15.0 degrees C. At what temperature would the joint be closed?
I would use the equation Change in L=L(alpha)T
But would the L equal zero since the joint is closed?
a copper cylinder(3 cm long) and a brass cylinder(5 cm long) are stacked end to end. each cylinder has a radius of .25 cm a compressive force of f=6500 N is applied to the right end of the brass where the other copper end is against a sollid object. find the amount by which the length of the...