- #1
furielrage
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An iron rod has a diameter of 2.50cm at 20.0°. To what temperature must it be heated to fit into a ring with an inside diameter of 2.51cm. I'm given: alpha=1.0x10^-5
I'm not sure how to apply it to the △L=(alpha)(object length)△T
I'm not sure how to apply it to the △L=(alpha)(object length)△T