For what reason is a magnetic force vector perpendicular to the magnetic field vector and the velocity vector of a charged particle? I know F=qvBsin and how to compute cross products but why does the force make a particle move in that particular direction? Is relativity involved?
A 60-N force is acting at 30° east of north and a second 60-N force acting in the direction 60° east of north are concurrent forces. Determine the resultant of the forces.
Using the Law of Cosines:
c²=a²+b²-2ab(CosC)
c²=13435.38
c=115.91 N for the magnitude of the resultant
Then...
i was given a graph and was told the find the X and Y components of the 2 vectors (C and D) and their Resultant R. i found the x,y components easily. now do i use the pythagorean theorem to find the resultant of C and D. and is that the answer? thanks ~Dave
(i have a graph, but it was too big...
two forces of 40N each act on something. the angle is 90 degree between the force. what is the magnitude of their resultant. my answer is 40 n. is that correct.
I should slap myself for not picking out what I did wrong but...
500 N are acting 140 degrees, 150 N are acting at 90 degrees and 420 N are acting at 60 degrees. Find the resultant.
the Resultant = (Rx^2 + Ry^2)^(1/2)
The angle of the resultant = arctan(Fy/Fx)
Correct?
Well, Fx =...