MHB -1.3.9 Verify ty'-y=t^2 is a solution of the DE

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The discussion verifies that the function y_1(t) = 3t + t^2 is a solution to the differential equation ty' - y = t^2. The calculation shows that substituting y_1 into the equation simplifies correctly to t^2. Participants note that the problem is straightforward, attributing its simplicity to the foundational principles of Calculus. Overall, the verification confirms that y_1(t) satisfies the differential equation. This reinforces the importance of understanding basic calculus concepts in solving differential equations.
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$\textsf{ Verify the following given functions is a solution of the differential equation}\\ \\$
$ty'-y=t^2\\$
$y_1(t)=3t+t^2$
\begin{align*}
t(3t+t^2)'-(3t+t^2)&=t^2\\
t(3+2t)-(3t+t^2)&=\\
3t+2t^2-3t-t^2&=\\
t^2&=t^2
\end{align*}

probably too easy
 
Last edited:
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Well, learning Calculus does make some problems easy!
 

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