A question about long-stroke or undersquare engines

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This discussion centers on the characteristics of long-stroke (undersquare) engines, specifically the BMW M3 (E46) and Lamborghini Murcielago LP640, which achieve high RPMs and power levels typically associated with short-stroke (oversquare) engines. The BMW M3 features an I-6 3.2L engine with a bore and stroke of 87 x 91 mm, while the Lamborghini Murcielago has a V12 6.5L engine with a bore and stroke of 88 x 89 mm. Key factors contributing to their performance include perfect primary and secondary balance in I6 and V12 configurations, as well as advanced engineering practices that allow for high compression ratios and effective force management within the engine design.

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As i have read in several articles, it is obvious that short-stroke or oversquare engines can rev higher and produce more power and less torque and usually used in sports cars but long-stroke engines are good for high low end torque and can't rev as high as short-stroke engines.

But i have seen some cars that have quite rev-happy engines (8000RPM) with so much power despite being undersquare.

Two examples are BMW M3 (E46) and Lamborghini Murcielago LP640

BMW M3 (E46) I-6 3.2L

Bore x Stroke = 87 x 91 (mm)

Lamborghini Murcielago LP640 V12 6.5L

Bore x Stroke = 88 x 89 (mm)

So, the above cars have long-stroke engines but with so much revs and power.

How can these cars manage to have the characteristics of an oversquare engine while being undersquare?
 
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They're only a bit undersquare, particularly the Lamborghini!

Aside from simple engineering factors (like reducing reciprocating mass and balancing components), the main factor here is that both I6 and V12 engines have perfect primary and secondary balance, unlike a straight four or V8.
 
brewnog said:
the main factor here is that both I6 and V12 engines have perfect primary and secondary balance, unlike a straight four or V8.
Thanks for your answer.
Could you explain this fact a little?
Why I6 and V12 engines have perfect primary and secondary balance?
 
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Typically textbooks start with the generalization that rpm is primarily limited by mean piston speed. While this is not exactly true, (mean piston speed by itself can barely hint at accelerations seen by the rotating equipment nor does it give any idication of the geometry) it's a good place to start.
 
good one brewnog..also con rod length ratio!
 
karabiner98k said:
As i have read in several articles, it is obvious that short-stroke or oversquare engines can rev higher and produce more power and less torque and usually used in sports cars but long-stroke engines are good for high low end torque and can't rev as high as short-stroke engines.

How can these cars manage to have the characteristics of an oversquare engine while being undersquare?

When discussing oversquare vs undersquare, you have to talk about the same cylinder displacement, otherwise there is no basis for comparison. The discussion then becomes one of stroke length and other things.
 
Size wise, if you want to compare engines, only the bore area is important.
Speed wise, if you want to compare engines, only the mean piston speed is important.

Check https://www.physicsforums.com/showpost.php?p=2770016&postcount=6" I've wrote on another thread.

The advantage of an undersquare engine is the possibility or creating higher compression ratio (which is why practically all diesel engines are undersquare).

The advantage of an oversquare engine is a smaller engine (volume wise, hence weight wise as well).
 
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I'm surprised you didn't mention most extreme example that I know of: Honda/ Acura Integra type R (B18C5)

4 cylinder
Bore: 81mm
Stroke: 87.2mm
Redline: 8,500rpm

The simple answer to your question is engineering. If you use better materials and better engineering practices, you can end up with some extreme characteristics.
 
  • #10
Just think, if they'd only made the engine oversquare and bumped the piston size up to 95 mm or so the engine would have made much more power.

So why aren't newer engines oversquare?
 
  • #11
mender said:
Just think, if they'd only made the engine oversquare and bumped the piston size up to 95 mm or so the engine would have made much more power.

So why aren't newer engines oversquare?

No low down torque (which is what most people use for every day driving), as mentioned above.

If you meant keeping the stroke the same but increasing bore - then you are incraesing displacement...
 
  • #12
xxChrisxx said:
No low down torque (which is what most people use for every day driving), as mentioned above.

If the engine specs are the same other than the bore to stroke relationship, an oversquare engine will have the same torque as an undersquare engine.

So why aren't newer engines oversquare?
 
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  • #13
I'm not enough of an expert to comment too much on your last post, but I believe undersquare do generally favor/ allow for more torque.

Whatever the case may be, sometimes there are other driving factors behind an engine design. The Acura/ Honda Type R that I mentioned, for example, is derived from the Integra GSR engine, which while still having the same dimensions, redlined at a lower 8000rpm and made about 25hp less. The engineers wanted a factory tuned "Type R" version of this car, and so they set themselves at squeezing more out of this engine. Despite its extreme characteristics, the engine performs extrmely well and reliably, and it was simply easier (and less expensive) to make more power this way than to completely redesign the entire engine/ car from scratch.
 
  • #14
Lsos said:
... but I believe undersquare do generally favor/ allow for more torque.
That is a myth that just won't die. Oversquare engines have the advantage in both torque and power production.

So why are newer engines designed to be undersquare? The original question that started this thread hasn't been answered yet.
 
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  • #15
mender said:
If the engine specs are the same other than the bore to stroke relationship, an oversquare engine will have the same torque as an undersquare engine.

So why aren't newer engines oversquare?

I think you'll find you are a bit off there. There are a coupe of reasons why stroked engines produce more torque, they are in Heywoods book on engine fundamentals.

One reason is that force decays away far quicker in an oversquare engine. So although you get a higher peak force value acting down the cylinder axis, most of the force is going into bending the crank rather than turning it. You get a pressure 'spike' close to TDC that decays away quickly, in a long stroke engine you get a force that decays away slower as the valume change per degree of crank angle is less.

There are a few other reasons but i'd have to read up on it in Heywood.

Think about it, if what you are saying WERE the case, all engines would have F1 style bore to stroke ratios. ie huge bores and tiny strokes. There would simply be no downside to doing it. It's for the very reason that they don't produce the same torque that engines are not oversquare.

You also can't really nail this down to one variable either, there are millions of interconnected reasons, as in an engine every variable affects almost every other variable.
 
  • #16
xxChrisxx said:
I think you'll find you are a bit off there. There are a coupe of reasons why stroked engines produce more torque, they are in Heywoods book on engine fundamentals.

One reason is that force decays away far quicker in an oversquare engine. So although you get a higher peak force value acting down the cylinder axis, most of the force is going into bending the crank rather than turning it. You get a pressure 'spike' close to TDC that decays away quickly, in a long stroke engine you get a force that decays away slower as the valume change per degree of crank angle is less.

There are a few other reasons but i'd have to read up on it in Heywood.

If the rod/stroke ratio is the same for both engines, the volume change/degree will be the same and pressure decay will also be the same.

xxChrisxx said:
.
It's for the very reason that they don't produce the same torque that engines are not oversquare.

Any other explanations as to why you think that? I see that statement a lot; I also build a lot of engines and dyno them. Did a new engine combo for a racing team just a few weeks ago that proves this wrong. Reduced the engine size by 5% to get a weight break yet lost only 2% torque and 1% power in the same rpm range despite increasing the bore to stroke ratio by 10%.

By the usual oversquare reasoning it should have lost at the minimum 5% torque output because of the displacement change and more because of the bore/stroke change.

xxChrisxx said:
.
Think about it, if what you are saying WERE the case, all engines would have F1 style bore to stroke ratios. ie huge bores and tiny strokes. There would simply be no downside to doing it. It's for the very reason that they don't produce the same torque that engines are not oversquare.

You also can't really nail this down to one variable either, there are millions of interconnected reasons, as in an engine every variable affects almost every other variable.

If power and torque production were the only considerations, every engine would be designed that way. There is another consideration that is more important; any guesses as to what that is?
 
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  • #17
I suspect that undersquare engine is limited by weakened parts. If the piston bore is increased, its height must be too to prevent rocking. But because the stroke is not increased, the piston pin has to move closer (in proportion) to the bottom edge of the piston to respect crankshaft clearance. The higher forces due to the larger piston are not supported by the (still the same) amount of material between the pin and the bottom edge.

Just an idea, nothing to support it.

mender said:
I also build a lot of engines and dyno them. Did a new engine combo for a racing team just a few weeks ago that proves this wrong. Reduced the engine size by 5% to get a weight break yet lost only 2% torque and 1% power in the same rpm range despite increasing the bore to stroke ratio by 10%.

By the usual oversquare reasoning it should have lost at the minimum 5% torque output because of the displacement change and more because of the bore/stroke change.

Mender, can you tell me more about this engine. I'm in a debate on another forum about the fact that power is only dependent on bore and that stroke don't change anything (like I say in https://www.physicsforums.com/showpost.php?p=2770016&postcount=6"). It looks like you have just prove that with your engine (it seems you only shorten the stroke without changing the bore, and by getting the same HP you are proving my point). Can you confirm that and give some numbers?

On the other forum, math is not seen as valuable tool to prove something, they want actual measurements.
 
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  • #18
The engine dimensions changed from 4.040 x 3.5 to 4.100 x 3.25; displacement respectively was 359 and 343, power output was 668 hp and 664 hp @ 7500 rpm, torque was 505 and 495 @ 6100 and 6200 rpm. Rod length was 6" for both, so R/S ratio changed slightly. Piston pin was lower by.125" because of the shorter stroke, piston weight was very close to the same. CR was 13.5:1 for both, and same quench. Hp per cube went from 1.86 to 1.94, torque per cube at peak was 1.41 and 1.44; not bad considering the application and budget. Both power and torque per cube improved by going more oversquare.

Rpm is limited to 8200 for valve train reliability (road course engine), so I couldn't take full advantage of the shorter stroke. I backed off on the cam specs ever so slightly as well, 2 degrees less intake duration and .010" less lift which likely accounts for the slight drop in hp. Everything else stayed the same; heads, intake, carb, exhaust system, ignition, air cleaner, oil pan and dry sump system.

I looked at your other post; to put it simply, the engine is an air pump and the more air that goes through, the power it makes. And since power is related to time, the more strokes per minute, the more power the engine makes as well. It's usually cylinder head flow that determines the hp limit.

Pistons can be quite short without strength issues, it's more about supporting the ring package properly. Given the advances in piston and rod design, the main limiting factor now is the valve train (as mentioned in your other post) and that is coming along nicely as well. It wasn't that long ago that 10,000 rpm was an incredible number; now we have production car engines that are approaching that.
 
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  • #19
Thank you mender, that is very helpful.
 
  • #20
xxChrisxx said:
I think you'll find you are a bit off there. There are a coupe of reasons why stroked engines produce more torque, they are in Heywoods book on engine fundamentals.

One reason is that force decays away far quicker in an oversquare engine. So although you get a higher peak force value acting down the cylinder axis, most of the force is going into bending the crank rather than turning it. You get a pressure 'spike' close to TDC that decays away quickly, in a long stroke engine you get a force that decays away slower as the valume change per degree of crank angle is less.

There are a few other reasons but i'd have to read up on it in Heywood.

Okay, I have a copy of Heywood's now; do you have page numbers? I've been leafing through the 900+ pages but haven't seen anything specific yet.
 
  • #21
First couple of chapters will have you sorted. It's actually quite a good bedtime book.
 
  • #22
xxChrisxx said:
One reason is that force decays away far quicker in an oversquare engine. So although you get a higher peak force value acting down the cylinder axis, most of the force is going into bending the crank rather than turning it. You get a pressure 'spike' close to TDC that decays away quickly, in a long stroke engine you get a force that decays away slower as the valume change per degree of crank angle is less.

There are a few other reasons but i'd have to read up on it in Heywood.

Think about it, if what you are saying WERE the case, all engines would have F1 style bore to stroke ratios. ie huge bores and tiny strokes. There would simply be no downside to doing it. It's for the very reason that they don't produce the same torque that engines are not oversquare.

You also can't really nail this down to one variable either, there are millions of interconnected reasons, as in an engine every variable affects almost every other variable.

mender said:
If the rod/stroke ratio is the same for both engines, the volume change/degree will be the same and pressure decay will also be the same.

If power and torque production were the only considerations, every engine would be designed that way. There is another consideration that is more important; any guesses as to what that is?

First, Chris, as mender pointed out, you're wrong about stating that bore/stroke ratio have something to do with the decompressing rate with respect to crankshaft angle. If you do the math, they are only 2 variables that affect that:
rod length/stroke ratio (smaller --> higher decompressing rate) and compression ratio (higher --> faster decompressing rate).

After thinking about it and doing a simple analysis, the bore/stroke ratio is limited by the surface-to-volume ratio (SVR) of the combustion chamber. For a given bore (which determines the power potential of your engine), the SVR increases with the bore/stroke ratio (higher SVR means more combustion chamber cooling - hence, energy loss - and creation of "dead spots" where the fuel mixture doesn't burn). By the same token, it should also reduce the squish zone. The problem gets worst as the CR increases (that's why diesel are normally undersquare).
 
  • #23
Sorry Jack, you're wrong here. Power is dependent on both bore and stroke. The quoted book would be your best source of enlightenment.
 
  • #24
mender said:
Okay, I have a copy of Heywood's now; do you have page numbers? I've been leafing through the 900+ pages but haven't seen anything specific yet.

My copy is back in Manchester, I've recently moved house so I've not shifted all my engineering books yet. It should be pretty near the front though.

I haven't had chance to read back up on it yet, it's why I've not posted anything on this.
 
  • #25
Okay, I've read the first two chapters and browsed most of the rest. He describes the relationships but doesn't make any claims that I saw. Let me know when you've located your book, I'm curious.

The overriding consideration that I was alluding to is emissions and fuel efficiency, both of which are better in undersquare engines and is a major reason for that trend in production engines even in the more exotic applications. Another significant advantage is reduction in octane sensitivity, allowing a higher specific output on pump gas.

Power and torque production are better in oversquare engines, which is why the vast majority of racing engines follow that trend.
 
  • #26
brewnog said:
Sorry Jack, you're wrong here. Power is dependent on both bore and stroke. The quoted book would be your best source of enlightenment.

I think Jack is referring to power being dependent on bore size and mean piston speed.
 
  • #27
mender said:
I think he's referring to power being dependent on bore size and mean piston speed.

Fair enough, but I'd picked up on this further up the page...

jack action said:
I'm in a debate on another forum about the fact that power is only dependent on bore and that stroke don't change anything (like I say in this post).
 
  • #28
I interpreted that to mean that stroke in itself doesn't dictate a change in the torque curve other than by the obvious displacement difference. I assume that you read his post.

Maybe Jack can expand on his thinking.
 
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  • #29
mender said:
I interpreted that to mean that stroke in itself doesn't dictate a change in the torque curve other than by the obvious displacement difference. I assume that you read his post.

Maybe Jack can expand on his thinking.

I'm not sure I understand clearly on what I should expand, because I always thought it was pretty obvious, so I will just repeat myself. In SI unit the power is define as such:

Power = torque * rpm

Torque can be related to the engine displacement & BMEP; and rpm can be related to mean piston speed (vp) and stroke (S):

Power = (BMEP * Engine displacement / (4 pi) ) * (vp / S * pi)

Replacing the engine displacement by its definition based on # of cylinders (N), bore (D) and stroke:

Power = (BMEP * (Ap * S) / (4 pi) ) * (vp / S * pi)

where: Ap = pi/4 * D² * N

The stroke from the engine displacement cancel the one from the rpm, leaving:

Power = BMEP * Ap * vp / 4

So, physically, only the total bore area (bore & # of cyl) is of importance. If you increase the stroke but do not reduce the rpm, then vp will increase and that will put the engine in an all new category, not comparable to the previous one. Furthermore, once you will reach the 30 m/s mark, you won't be able to increase vp further as your piston will travel faster than the flame front.

If you increase the stroke but keep the same vp, you will get the same power but the torque will increase because the rpm will be reduced. So, if you change only the stroke from Sold to Snew and keep the top end components the same (camshaft & cylinder head), you will basically only see a shift of the power curve by a factor Snew / Sold (the intake & exhaust lengths are tuned with rpm, so it may make some little difference if the change is too radical and the engine is well tuned). But it doesn't change anything as it is only a matter of choosing a proper gear ratio to go back to the original values of torque & rpm.

IMHO, stroke is basically a gear ratio that is more efficient. Of course, long stroke means bigger engine and more weight so it has to be taken into consideration as well.

And there is no magic in this as:

volume flow rate = Ap * vp / 4

So:

Power = BMEP * volume flow rate

Which is true for any engine (4-stroke, 2-stroke, CI, SI and even gas turbine).

Yes, a bigger engine draws more air per rev, but it also rev slower, so in the end it has the same flow rate.
 
  • #30
That's what I understood you to say before, Jack, but thanks for restating it.

As has been said, there are quite a few variables that add up to a particular torque curve but the bore/stroke ratio doesn't have a direct effect on the shape of the curve.
 

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