[SOLVED] Amount of 6M H2SO4 to lower pH of pool from 7.0 to 4.0 1. The problem statement, all variables and given/known data A new swimming pool is filled with fresh, clean water with a pH of 7.0. The width is 25 ft, the length is 60 ft, and the depth linearly ranges from 3.5 to 9 ft. How much 6 M H2SO4 must be added to reduce the water pH to 4.0 so that the plaster liner in the pool can be cured? 2. Relevant equations kw = ka*kb, pKa = -log(Ka) and for pOH and pH, any the usual concentration formulas. 3. The attempt at a solution I'm honestly not entirely sure how to tackle this. I first started off by finding things I may need. I found the capacity of the pool to be 265,643 liters. The molecular weight of H2SO4 is 98.065 g/mol. Ka of H2SO4 is 10^3. If you guys could bump me in the right direction it'd be appreciated. Thanks!