The concentration of HCl in a bottle was determined as follows:
* 4.00 mL of the acid were diluted to 150.00 mL
* 26.53 mL of the diluted acid were titrated with 0.08329-M NaOH
* 43.91 mL of the base were required to reach the end point
What is the HCl concentration in the bottle?
Possibly C(final)=C(initial)*(v(1)/v(2))*(v(3)/v(4))* ,....
The Attempt at a Solution
C(initial)= .08329 M
For end Volume I assume that be V(4) and V(3) would be the titrated volume.
C(final)=.08329 M *(4 mL/150 mL)*(26.53 mL/43.91mL)= .00134 M