Are Minimal Left Ideals in Hassani's Algebra Always Trivial?

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Discussion Overview

The discussion revolves around the concept of minimal left ideals in Hassani's algebra, particularly questioning whether they are always trivial, specifically focusing on the implications of defining minimal left ideals and the role of the zero set in this context.

Discussion Character

  • Debate/contested
  • Technical explanation

Main Points Raised

  • Some participants clarify the definition of left ideals and minimal left ideals as presented in Hassani's text, noting that the zero vector is a left ideal of any algebra.
  • One participant suggests that the author may have intended to specify 'non-trivial' or 'nonzero' left ideals, as the zero set being the only minimal left ideal renders the concept uninteresting.
  • Another participant expresses confusion regarding a theorem in the book that states an automorphism of an algebra is an isomorphism among its minimal ideals, questioning the relevance of the kernel of an injective linear map in this context.
  • Some participants agree that if minimal ideals are defined as nonzero, the theorem remains valid, but they challenge the relevance of Hassani's comments regarding the kernel and the zero set.

Areas of Agreement / Disagreement

Participants generally disagree on the interpretation of minimal left ideals, particularly regarding the inclusion of the zero set as a minimal left ideal. There is no consensus on whether Hassani's definitions are complete or if they require clarification.

Contextual Notes

The discussion highlights potential limitations in the definitions provided in Hassani's text, particularly concerning the treatment of the zero set and its implications for the concept of minimal left ideals.

Geofleur
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In the chapter on Algebras in Hassani's mathematical physics text, left ideals are defined as follows:

Let ## \mathcal{A} ## be an algebra. A subspace ## \mathcal{B} ## of ## \mathcal{A} ## is called a left ideal of ## \mathcal{A} ## if it contains ## \mathbf{a}\mathbf{b} ## for all ## \mathbf{a}\in \mathcal{A} ## and ## \mathbf{b} \in \mathcal{B} ##.

He then defines a minimal left ideal:

A left ideal ## \mathcal{M} ## of an algebra ## \mathcal{A} ## is called minimal if every left ideal of ## \mathcal{A} ## contained in ## \mathcal{M} ## coincides with ## \mathcal{M} ##.

Here is where I am confused. The set containing only the zero vector is a subspace of any vector space, because ## \alpha \mathbf{0} + \beta \mathbf{0} = \mathbf{0} ## for any scalars ## \alpha ## and ## \beta ##. Moreover, the set containing the zero vector is a subalgebra of any algebra, because ## \mathbf{0} \mathbf{0} = \mathbf{0} ##. In fact, the "zero set" is a left ideal of any algebra, because ## \mathbf{a} \mathbf{0} = \mathbf{0} ## for any ##\mathbf{a} \in \mathcal{A} ##. But then the only minimal left ideal is just the zero set, because every left ideal has the zero vector as an element. This conclusion would make the whole concept of minimal ideals rather uninteresting. Am I going wrong somewhere here?
 
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@Geofleur, your logic appears to be flawless. The subalgebra {0} is indeed a left ideal of A that is contained in any other left ideal M.

I'm pretty sure that the author just forgot to insert the words 'non-trivial' or 'nonzero' before 'left ideal'. If we compare his/her definition here with that on Wikipedia for minimal ideals of rings, we see that the 'nonzero' requirement is stipulated.

I suggest proceeding on the assumption that the author meant 'nonzero' but forgot to specify that.

See also this wiki page on Simple Algebras, which refers to 'minimal nonzero left ideals' of an algebra, which suggests that things only become interesting when one considers ideals that properly contain no nonzero ideals.
 
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OK, I'm glad that I am not totally off-base. On the other hand, what happens next in the book, when I make the assumption that a minimal left ideal cannot be the zero set, has me thoroughly puzzled. There comes a theorem (I've bolded the troublesome part):

Let ## \mathcal{A} ## and ## \mathcal{B} ## be algebras, ## \phi : \mathcal{A} \rightarrow {\mathcal{B}} ## an epimorphism, and ## \mathcal{L} ## a minimal left ideal of ## \mathcal{A}##. Then ##\phi(\mathcal{L})## is a minimal left ideal of ##\mathcal{B}##. In particular, any automorphism of an algebra is an isomorphism among its minimal ideals.

The problem is with this last statement, together with the comment: "The last statement of the theorem follows from the fact that ker ##\phi## is an ideal of ##\mathcal{A}##."

Now, an automorphism is defined as an isomorphism of an algebra onto itself. An isomorphism is, among other things, an injective linear map. But the kernal of an injective linear map must be the zero set, for suppose ## \mathbf{a} \in ## ker ##\phi##. Then ##\phi(\mathbf{a}) = \mathbf{0} = \phi(\mathbf{0}) ##. Hence, ##\mathbf{a}=\mathbf{0}## because ## \phi ## is injective. So Hassani seems to be saying to think of the zero set as an ideal. If he does not want to consider the zero set as a minimal left ideal, I don't see how the comment is relevant to proving the last statement of the theorem. If he does want to consider the zero set as a minimal left ideal, then the concept of minimal left ideal is rendered trivial. Any ideas?
 
Agreed. Although this statement:

Geofleur said:
Let ## \mathcal{A} ## and ## \mathcal{B} ## be algebras, ## \phi : \mathcal{A} \rightarrow {\mathcal{B}} ## an epimorphism, and ## \mathcal{L} ## a minimal left ideal of ## \mathcal{A}##. Then ##\phi(\mathcal{L})## is a minimal left ideal of ##\mathcal{B}##. In particular, any automorphism of an algebra is an isomorphism among its minimal ideals.

is still true if we define a minimal ideal as nonzero. His comment however

The problem is with this last statement, together with the comment: "The last statement of the theorem follows from the fact that ker ##\phi## is an ideal of ##\mathcal{A}##."

Is completely irrelevant.

Anyway, welcome to Hassani. I tried to like the book, but it is filled with stuff like this. It's way better to learn from actual math books.
 
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Thanks so much!
 

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