Are phottons effected by gravity?

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SUMMARY

Photons are indeed affected by gravity, as they follow the curvature of spacetime created by massive objects. When the escape velocity of a celestial body exceeds the speed of light, photons cannot escape, particularly evident in black holes where the event horizon marks this boundary. Gravitational lensing occurs when light bends around massive objects, illustrating how gravity influences light's path. The distinction between velocity and acceleration is crucial, as 9.8 m/s² represents gravitational acceleration, not a direct comparison to the speed of light.

PREREQUISITES
  • Understanding of general relativity and spacetime curvature
  • Familiarity with the concept of escape velocity
  • Knowledge of black holes and event horizons
  • Basic physics principles regarding velocity and acceleration
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  • Study the properties and implications of black holes and their event horizons
  • Explore the principles of general relativity as formulated by Albert Einstein
  • Learn about the differences between velocity and acceleration in physics
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Some days ago some body posted a question saying are photons effected by gravity but was unanswered straightly. Here is the answer: Yes they are. They will be completely be stopped if an escape velocity of a planet is greater than the speed of light.
 
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First off, its 'photon'. Secondly, light isn't so much "affected" by gravity as it just follows the path of least resistance through space just as any object would. So if gravity were strong enough to form a rather deep gravity well, then light would bend through the path like a marble encountering a dent in the floor it's rolled across. That's how gravitational lensing works. Starlight encounters the gravity well of a rather large mass (star) and follows the curvature of spacetime forming an image of a star blocked from view by the object. A black hole can form a large enough gravity well to pull light beyond the event horizon were it can't escape.
 
really?

I was reading like: If at all a photons tries to escape a black hole in which the escape velocity is higher than the speed of light the photon will never be able to escape. Is that not true? ofcource a photon is bearly affected. Like i said i am telling an answer. What is 9.8 m/s compaered to 3.00*10^8?
 
A black hole, by definition, is a body whose escape velocity is, at some altitude, greater than the speed of light. The mathematical surface surrounding such a body is called an 'event horizon.' On or inside this surface, the escape velocity exceeds c.

And the number 9.8 is not a velocity -- it's an acceleration -- m/s2. You cannot compare a velocity and an acceleration, because they mean different things.

- Warren
 
Originally posted by anil
Some days ago some body posted a question saying are photons effected by gravity but was unanswered straightly. Here is the answer: Yes they are. They will be completely be stopped if an escape velocity of a planet is greater than the speed of light.

see this site answer


BTW.. "Secondly, light isn't so much "affected" by gravity" this is incorrect it is. see explanantion
ans2

good topic!
Dx :wink:
 


Originally posted by Dx
see this site answer


BTW.. "Secondly, light isn't so much "affected" by gravity" this is incorrect it is. see explanantion
ans2

good topic!
Dx :wink:

Well I sort of ment not in the way that gravity affects objects with mass.
 

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