- #1

karush

Gold Member

MHB

- 3,269

- 5

\[ \dfrac{dy}{dx} =\dfrac{x^2+3y^2}{2xy} =\dfrac{x^2}{2xy}+\dfrac{3y^2}{2xy} =\dfrac{x}{2y}+\dfrac{3y}{2x}\]

ok not sure if this is the best first steip,,,, if so then do a $u=\dfrac{x}{y}$ ?

ok not sure if this is the best first steip,,,, if so then do a $u=\dfrac{x}{y}$ ?

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