- #1

CoinToss

- 11

- 0

## Homework Statement

Balance the following Chemistry equation, you are allowed to add H{+} and H2O where needed

Given

C

_{6}H

_{5}OCl + NO

_{3}

^{-}--> N

_{2}+ Cl

^{-}+ CO

_{2}

**2. The attempt at a solution**

Balance the carbon first:

C

_{6}H

_{5}OCl + NO

_{3}

^{-}--> N

_{2}+ Cl

^{-}+ 6CO

_{2}

Increase Oxygen O in NO3{-} to compensate; also increase N on RHS

C

_{6}H

_{5}OCl + 4NO

_{3}

^{-}--> 2N

_{2}+ Cl

^{-}+ 6CO

_{2}

Bring out the H{+} and O{2-} on RHS

C

_{6}H

_{5}OCl + 4NO

_{3}

^{-}--> 2N

_{2}+ Cl

^{-}+ 6CO

_{2}+ H2O + 3H

^{+}

Multiply both sides by 2

2C

_{6}H

_{5}OCl + 8NO

_{3}

^{-}--> 4N

_{2}+ 2Cl

^{-}+ 12CO

_{2}+ 2H

_{2}O + 6H

^{+}

Compensate for 6H{+} on RHS by increasing NO3 by 1 to form H2O on RHS

2C

_{6}H

_{5}OCl + 9NO

_{3}

^{-}--> 4N

_{2}+ 2Cl

^{-}+ 12CO

_{2}+ 5H

_{2}O + N

^{3-}

At this point I would assume that H{+} Is required on the LHS to give N2 and H2O on RHS

2C

_{6}H

_{5}OCl + 10NO

_{3}

^{-}+ 2H

^{+}--> 5N

_{2}+ 2Cl

^{-}+ 12CO

_{2}+ 6H

_{2}O

Which is looking pretty good so far-- except the charges on either side are not balanced. And this would be the point where I am stuck. Was there supposed to be a different approach to this? I appreciate your time. Thank you.