Balancing Equation using redox reactions?

Click For Summary
SUMMARY

The discussion focuses on balancing the redox reaction involving oxygen difluoride (OF2) in a basic solution, producing fluoride ions (F-), oxygen (O2), and water (H2O). The user successfully balanced part of the reaction using H2O and H+ ions but seeks clarification on completing the balance using half-reactions. The problem specifically requires the application of oxidation numbers and half-reaction methods to achieve the correct stoichiometry.

PREREQUISITES
  • Understanding of redox reactions and their components
  • Knowledge of half-reaction method for balancing equations
  • Familiarity with oxidation states and their calculations
  • Basic chemistry concepts related to acidic and basic solutions
NEXT STEPS
  • Study the half-reaction method for balancing redox reactions in basic solutions
  • Learn how to calculate oxidation numbers for different elements in compounds
  • Research the role of hydroxide ions (OH-) in redox reactions
  • Explore examples of balancing complex redox reactions in aqueous solutions
USEFUL FOR

Chemistry students, educators, and professionals involved in redox chemistry, particularly those focusing on balancing reactions in basic solutions.

r_swayze
Messages
65
Reaction score
0
OF2 --> F- + O2 + H2O

OF2 --> F-

2H+ +OF2 --> 2F- + H2O

2H+ +OF2 + 4e- --> 2F- + H2O

This is as far as I can get. I don't know how to do the other half of the redox since the equation would be:

OF2 --> O2 + H2O

What do I do here? Maybe I am not setting this up correctly?
 
Physics news on Phys.org
Please elaborate a little bit.

Are you expected to use oxidation numbers or half reactions?

Anything about conditions - low pH, high pH, just hydrolysis in water?

--
 
The problem states:

"Balance the following redox reaction:

In basic solution, oxygen difluoride reacts to produce fluoride ion, oxygen, and water."

I figured out one way of doing it by just adding H2O, H^+ ions, and OH^- ions to either side and balancing it, but I want to know how to do it using half reactions.
 
Assume OH- is being oxidized to O2 and water.

--
 

Similar threads

Replies
7
Views
2K
  • · Replies 18 ·
Replies
18
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
5
Views
1K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K