Balancing Oxidation-Reduction Reaction

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SUMMARY

The discussion focuses on balancing oxidation-reduction reactions, specifically the reaction involving permanganate ions (MnO4^(-)) and methanol (CH3OH). The correct balanced equation is 4MnO4^(-) + 5CH3OH + 12H^(1+) → 4Mn^(2+) + 5HCO2H + 12H2O. The oxidizing agent is identified as MnO4^(-), while the reducing agent is CH3OH. The participant initially struggled with balancing the reaction but ultimately provided the correct answer as per the textbook.

PREREQUISITES
  • Understanding of oxidation-reduction reactions
  • Familiarity with balancing chemical equations
  • Knowledge of oxidation states and electron transfer
  • Basic concepts of permanganate ion chemistry
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  • Study the principles of balancing redox reactions in acidic and basic solutions
  • Learn about the role of permanganate as an oxidizing agent in organic reactions
  • Explore the concept of half-reactions in redox processes
  • Investigate common mistakes in balancing oxidation-reduction reactions
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Chemistry students, educators, and professionals involved in chemical analysis or organic synthesis who seek to enhance their understanding of redox reactions and balancing techniques.

Dove99x
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1. Complete and balance the following equations, and identify the oxidizing and reducing agents:

OXIDATION.png
2. Rules.

1) an element that is reduced Gains electrons and loses Oxygen

2) an element that is oxidized loses electrons but gains Oxygen

3. My attempt

Oxidizing Agent: 5e + 8H + MnO4 ^(1-) ---> Mn ^(2+) + 4H2O

Reducing Agent: 2H2O + CH4O ---> H2CO2 + 6H ^(1+) + 6e
--------------------------------------------------------------------


At this point I relize that what I'm doing is totally wrong. I don't know how to solve this.

4. Correct Answer from Book:

4MnO4 ^(1-) + 5 CH3OH + 12 H ^(1+) ---> 4Mn ^(2+) + 5HCO2H + 12 H2O
 
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Dove99x said:
Oxidizing Agent: 5e + 8H + MnO4 ^(1-) ---> Mn ^(2+) + 4H2O

Correct.

Reducing Agent: 2H2O + CH4O ---> H2CO2 + 6H ^(1+) + 6e

Oxygen is not balanced.
 

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