Calculating Delta P in Vacuum Chambers: P1 or 0?

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SUMMARY

In vacuum chambers, calculating delta P (ΔP) requires understanding the pressure conditions involved. When air is absent, ΔP cannot be calculated as both P1 and P2 approach zero, resulting in no driving force. The discussion emphasizes that without external pressure, such as in the case of a shaken cola can in a vacuum, the ΔP is effectively zero, leading to no force upon opening. Therefore, in vacuum conditions, P1 should not be substituted with zero, as it negates the existence of ΔP.

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ahmed11
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in calculating the delta p in vacuum chambers do we substitute p1 with 0 or the whole equation doesn't exist if air doesn't exist?
 
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Could you elaborate on what it is that you are exactly talking about?
 
CrazyNinja said:
Could you elaborate on what it is that you are exactly talking about?
i mean if we shook a cola can in vacuum chamber then the driving force when opened will be zero because there is no delta p. right?
without air then there won't be delta p.
or we assume that p 1 is equal to p2 is equal to zero?
do you get what i mean
 
Why do you think there is no ΔP? (In case you are wondering, there is a "symbols" section in the text from where you can get a "Δ" ). The cola bottle is packed with high pressure and the pressure outside is close to zero.
 

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