Calculating Force on Wheaties from Cheerios: 28 N

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SUMMARY

The discussion centers on calculating the force exerted on a box of Wheaties by a box of Cheerios when a horizontal force of 28 N is applied to the Cheerios box. The mass of the Cheerios box is 1.2 kg, and the mass of the Wheaties box is 3.7 kg, with frictional forces of 1.6 N and 6.3 N acting on each box, respectively. The solution confirms that the forces applied by both boxes are equal, leading to the conclusion that the force on the Wheaties box from the Cheerios box is 28 N minus the frictional force acting on the Cheerios box.

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Homework Statement
A box of Cheerios (mass mC = 1.2 kg) and a box of Wheaties (mass mw = 3.7 kg) are accelerated across a horizontal surface by a horizontal force F applied to the Cheerios box. The magnitude of the frictional force on the Cheerios box is 1.6 N, and the magnitude of the frictional force on the Wheaties box is 6.3 N. If the magnitude of F is 28 N, what is the magnitude of the force on the Wheaties box from the Cheerios box?

The attempt at a solution

I need some help setting this up. Shouldn't the magnitudes of the forces applied by both boxes equal each other?
 
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I was able to solve it.
 

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