Calculating Passengers without Caps or Eye Glasses: 36 Bus Riders

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Homework Statement


Out of 36 passengers in a bus. 8 have caps, 2 have both cap and eye glasses , 26 don't have eye glasses, how many passengers have neither caps nor eye glasses


Homework Equations





The Attempt at a Solution



A draw 2 intersected diagrams C and E. In C I write 6 dots, in the intersected point i write 2 dots, but I don't know how many should I write in Diagram E(Eyeglasses)
The formula: C U E = C + E - CinteresectE
 
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You could draw venn diagrams etc.. but also consider the algebraic approach using the relation you gave at the bottom of your post. Have you come across DeMorgan's Laws?
 
blunted said:

Homework Statement


Out of 36 passengers in a bus. 8 have caps, 2 have both cap and eye glasses , 26 don't have eye glasses, how many passengers have neither caps nor eye glasses


Homework Equations





The Attempt at a Solution



A draw 2 intersected diagrams C and E. In C I write 6 dots, in the intersected point i write 2 dots, but I don't know how many should I write in Diagram E(Eyeglasses)
The formula: C U E = C + E - CinteresectE

Perhaps you should think how many to put outside area E. You already have 6 outside that area.