MHB Can a bipartite graph have two non-connected parts?

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A bipartite graph can indeed be disconnected, allowing for multiple non-connected components. Each component can still maintain the bipartite property, meaning it can be divided into two distinct sets of vertices. The notation $G=(U,V,E)$ is used to represent the graph's bipartition, which can vary if the graph is not connected. Therefore, the example of vertices A and B connected to C and D illustrates a valid bipartite structure. Understanding these properties is crucial for applications involving bipartite graphs.
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For example vertice A connected to vertice B and vertice C connected to vertice D? Would this be considered two different graphs? Here is a graph, would it be bipartite?
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Re: can a bipartite graph have two not connected parts?

A bipartite graph can be disconnected. Wikipedia says: "One often writes $G=(U,V,E)$ to denote a bipartite graph whose partition has the parts $U$ and $V$, with $E$ denoting the edges of the graph. If a bipartite graph is not connected, it may have more than one bipartition; in this case, the $(U,V,E)$ notation is helpful in specifying one particular bipartition that may be of importance in an application".
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...

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