KOO
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Prove that every n E N can be written as a product of odd integer and a non-negative integer power of 2.
For instance: 36 = 22 * 9
For instance: 36 = 22 * 9
Every natural number \( n \) can be expressed as a product of an odd integer and a non-negative integer power of 2. For odd integers, the expression is \( n = n \cdot 2^0 \). For even integers, including zero, the expression takes the form \( n = 2^k \cdot m \), where \( m \) is an odd integer. This decomposition can be rigorously proven using strong induction and repeated division by 2, confirming the validity of the claim.
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KOO said:Prove that every n E N can be written as a product of odd integer and a non-negative integer power of 2.
For instance: 36 = 22 * 9
This is not enough to prove the required claim.Prove It said:If n is odd, we can write it as \displaystyle \begin{align*} n = n \cdot 2^0 \end{align*}.
If n is even (including 0), it must have a factor of 2, so we can write it as \displaystyle \begin{align*} n = 2^1 k \end{align*}.
What about powers of 2? 2^k (k being a positive integer) has no odd factors, unless you want to include 1.KOO said:Prove that every n E N can be written as a product of odd integer and a non-negative integer power of 2.
For instance: 36 = 22 * 9
Well, we want to include 1. Thus, if $k$ is a nonnegative integer, then $2^k=1\cdot2^k$: here 1 is an odd integer and $2^k$ is a non-negative integer power of 2, so this factorization satisfies the problem statement.topsquark said:What about powers of 2? 2^k (k being a positive integer) has no odd factors, unless you want to include 1.