Can you help me find the osmolarity of this KNO3 solution?

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Discussion Overview

The discussion revolves around calculating the osmolarity of a KNO3 solution, specifically focusing on a 0.500 liter solution containing 132g of KNO3. Participants are attempting to solve a homework problem related to this topic.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents an attempt at calculating osmolarity, arriving at a value of 5.224, based on a calculation of 1.306 mol in 0.500 L and considering the dissociation of KNO3 into two ions.
  • Another participant provides a different calculation, yielding 2.612, and questions the assumption of the solution volume being 1L instead of 0.500L.
  • A third participant confirms the solution volume is indeed 0.500L and expresses uncertainty about how to proceed with the calculations.
  • A fourth participant reiterates the volume and asks for the updated answer after reworking the equation.

Areas of Agreement / Disagreement

Participants generally agree on the volume of the solution being 0.500L, but there are differing calculations regarding the osmolarity, leading to unresolved discrepancies in the answers provided.

Contextual Notes

Participants have not provided specific equations or definitions related to osmolarity, and the calculations depend on assumptions about the dissociation of KNO3 and the molarity of the solution.

oceanbreeze
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Homework Statement



I tried to solve this question, but I'm not sure if my answer is correct.

What is the osmolarity of a 0.500 liter solution containing 132g of KNO3?

Homework Equations



N/A

The Attempt at a Solution



1.306 mol/0.500 L solution x 2 mol ions/1 mol KNO3 = 5.224
 
Last edited:
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oceanbreeze said:

Homework Statement



I tried to solve this question, but I'm not sure if my answer is correct.

What is the osmolarity of a 0.500 liter solution containing 132g of KNO3?

Homework Equations



N/A

The Attempt at a Solution



1.306 mol/1 L solution x 2 mol ions/1 mol KNO3 = 2.612

What is the volume of solution? You seem to have assumed it to be 1L.
 
It's 0.500L. I've reworked the equation, but I'm not sure how to proceed.
 
oceanbreeze said:
It's 0.500L. I've reworked the equation, but I'm not sure how to proceed.

What answer do you reach now?
 

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