Can you solve the equation 100! - 99!?

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Discussion Overview

The discussion revolves around the mathematical expression 100! - 99!, exploring its simplification and computation. Participants engage in breaking down the factorials and consider different approaches to the problem.

Discussion Character

  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant proposes letting x = 99! and derives that 100! - 99! simplifies to 99 * 99!.
  • Another participant confirms this simplification, stating that 100! - 99! equals 99!(100 - 1) = 99!(99).
  • A third participant agrees with the simplification but questions the need to compute 99! further, suggesting it would be a waste of time.
  • One participant mentions the use of Mathematica for evaluating the expression.
  • A later reply humorously notes that the factorial operation does not satisfy the distributive law.

Areas of Agreement / Disagreement

Participants generally agree on the simplification of the expression to 99 * 99!, but there is no consensus on whether further computation is necessary or useful.

Contextual Notes

Some participants express uncertainty about the necessity of computing 99! directly, suggesting that it may not provide additional insights into the simplification.

srfriggen
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question: what is 100! - 99!

I've broken it down to a problem like this: Let x=99! Then 100! = 100*99! = 100x. 100x - x=99x = 99*99!.

I can't figure out a way to simplify the problem any more than that.

Thank you in advance for any help.
 
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There is the obvious: 100!- 99!= 99!(100- 1)= 99!(99).
 
you've got the right answer and I don't see how it COULD be simplified any further except by actually computing 99! which just seems like a waste of time.
 
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http://www.wolframalpha.com/input/?i=99*99!&dataset=

attachment.php?attachmentid=62587&stc=1&d=1381162058.gif


Edit: lol, too much time spent to attach the image.
 

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As is seen, "!" does not satisfy the distributive law for operations. :smile:
 

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