Cauchy-Euler Diff. Eqn: Transformation & Solution

  • Context: Undergrad 
  • Thread starter Thread starter Arman777
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Discussion Overview

The discussion revolves around the Cauchy-Euler differential equation and the transformation technique using the substitution \( x = e^t \). Participants explore the process of transforming derivatives, specifically how to express \( \frac{dy}{dx} \) and \( \frac{d^2y}{dx^2} \) in terms of \( t \) and the implications of this transformation.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant presents the Cauchy-Euler differential equation and expresses confusion about transforming \( \frac{dy}{dx} \) to \( \frac{dy}{dt} \).
  • Another participant suggests using the product rule for derivatives to differentiate \( \frac{f}{x} \) with respect to \( x \).
  • A participant derives \( \frac{dy}{dx} = \frac{f}{x} \) and \( \frac{d^2y}{dx^2} = \frac{df}{dx} \frac{1}{x} - \frac{f}{x^2} \), but expresses uncertainty about relating \( \frac{df}{dx} \) to \( \frac{d^2y}{dt^2} \).
  • Another participant asks for clarification on expressing \( \frac{df}{dx} \) in terms of \( \frac{df}{dt} \).
  • A participant confirms understanding after realizing that \( \frac{df}{dx} = \left(\frac{df}{dt}\right)\left(\frac{dt}{dx}\right) \).

Areas of Agreement / Disagreement

Participants do not reach a consensus on the transformation process, as some express confusion while others provide clarification. The discussion remains unresolved regarding the specific relationship between the derivatives.

Contextual Notes

There are limitations in the discussion regarding the assumptions made during the transformation process and the dependence on the definitions of the derivatives involved. Some mathematical steps remain unresolved.

Arman777
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Cauchy-Euler is a type of diff equation which is described by

$$a_0x^2(\frac {d^2y} {dx^2})+a_1x(\frac {dy} {dx})+a_2y=F(x)$$

The transformation of ##x=e^t## can solve the equation.

Now, in here I didnt understand how to transform ##\frac {dy} {dx}## to ##\frac {dy} {dt}##.

it goes like this ##\frac {dy} {dx}=\frac {dy} {dt} \frac {1} {x}## and then I am stuck I should take another derivative but I couldn't do it somehow.
 
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Let ##dy/dt = f## and apply the product rule for derivatives when differentiating ##f/x## wrt x.
 
Orodruin said:
Let ##dy/dt = f## and apply the product rule for derivatives when differentiating ##f/x## wrt x.
Okay hmm

##\frac {dy} {dx}=\frac {f} {x}##
##\frac {d^2y} {dx^2}=\frac {df} {dx} \frac {1} {x}-\frac {f} {x^2}##

now I understand until here, but I didnt understand this term ##\frac {df} {dx}=\frac {d^2y} {dt^2}\frac {1} {x}## which its done in the book.
 
What is ##df/dx## in terms of ##df/dt##?
 
Orodruin said:
What is ##df/dx## in terms of ##df/dt##?
##df/dx=(df/dt)(dt/dx)##

I understand it now, thanks :angel:
 

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