Centripetal force stunt driver problem

[xcortz]

Homework Statement

A stunt driver for a movie needs to make a 2545kg car skid on a large, flat, parking lot surface. The force of friction between the tires and the concrete surface is 1.75x10^4N and he is driving at a speed of 24m/s. As he turns more sharply, what radius of curvature will he reach when the car just begins to skid? (Ans: 83.8m)

Homework Equations

Fc=(m)(v)^2/r

The Attempt at a Solution

1.75x10^4N=(2545kg)(24m/s)^2/r
1.75x10^4N=1,465,920/r
0.011937m=r

 

[RUber]

You solved for 1/r.