Characteristic Zero: Explaining Rationals & Subfield Isomorphism

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SUMMARY

Every field of characteristic zero contains a subfield that is isomorphic to the rationals. This is established by demonstrating that the integers can be embedded within the field, as the characteristic being zero ensures that sums of the form 1+1+...+1 (k times) do not equal zero. Consequently, the field includes elements of the form n*(1/m) for integers n and m, which leads to the conclusion that the subfield formed by these elements is isomorphic to the rational numbers.

PREREQUISITES
  • Understanding of field theory and characteristics of fields
  • Familiarity with the concept of isomorphism in algebra
  • Knowledge of integer and rational number properties
  • Basic operations in abstract algebra
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  • Study the properties of fields in abstract algebra
  • Learn about field isomorphisms and their implications
  • Explore the concept of characteristic in fields
  • Investigate examples of fields with characteristic zero, such as the field of rational numbers
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Can anyone explain to me why each field of characteristic zero contains a copy of the rationals, or a subfield that's isomorphic...
 
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If you have a field with characteristic zero.

1 is in the field. Also, 1+1 is in the field. And 1+1+1, etc. Let's call 1+1 2 for now, 1+1+1 3 for now. Since the characteristic is zero, none of these are zero, so the map 1+1+...+1 k times can be mapped to k, and -1-1-1...-1 k times can be mapped to -k and we have a copy of the integers inside the field.

Not only do we have the integers, but since it's a field, we also have 1/2, 1/3, etc. anything of the form 1/m for m an integer (non-zero) and since it's closed under multiplication, we have everything of the form n*(1/m) where n and m are integers in the field (so elements of the form 1+1+1... or -1-1-1...) The map n/m (the rational number) to n*(1/m) (the product in the field) gives you that the subfield of all things of the form n*(1/m) is in fact isomorphic to the rationals
 

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