Charge on 7 mF Capacitor Connected to 1 V Battery

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SUMMARY

When three capacitors with capacitances of 5 mF, 7 mF, and 2 mF are connected in series to a 1 V battery, the charge on the positive plate of the 7 mF capacitor is not equal to 7 µC. Instead, the charge on each capacitor in a series circuit is the same, and the voltage across each capacitor varies. The total capacitance for capacitors in series is calculated using the formula 1/C_total = 1/C1 + 1/C2 + 1/C3, leading to a different charge calculation than initially assumed.

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GravityGirl
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Three capacitors of capacitance 5, 7, and 2 mF respectively, are connected in series to a 1 V battery. What is the charge on the positive plate of the 7 mF capacitor?

so if the capacitors are all connected to the battery... than all of them have to have a electrial potential of 1 v

since C=Q/V, then CV=Q

and then i have (7 x10^-6 F)*1V=Q which is 7x10^-6 C

that is what i am getting, but it seems to be wrong. please help me out
 
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The capacitors are in series, so there is no requirement that they must have the same voltage across them.

- Warren
 
ok i got it.
 

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