Chemical equation for glucose osazone and limiting reactants

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SUMMARY

The discussion centers on calculating the theoretical mass of glucose osazone (C18-H22-N4-O4) using the chemical equations involving phenylhydrazine (C6-H5-N2-H3). The participant identifies the limiting reactants in the first reaction and debates whether to use a 2:1 or 3:1 molar ratio of phenylhydrazine to osazone for yield calculations. The conversation also touches on the implications of using different sources of phenylhydrazine and the potential need to revise existing literature based on new findings regarding neutralization reactions.

PREREQUISITES
  • Understanding of chemical equations and stoichiometry
  • Knowledge of limiting reactants in chemical reactions
  • Familiarity with phenylhydrazine (C6-H5-N2-H3) and glucose osazone (C18-H22-N4-O4)
  • Basic principles of neutralization reactions
NEXT STEPS
  • Research the stoichiometry of phenylhydrazine reactions with glucose
  • Study the implications of limiting reactants on theoretical yield calculations
  • Explore the role of sodium acetate in neutralization reactions
  • Investigate the synthesis and properties of glucose osazone
USEFUL FOR

Chemistry students, laboratory researchers, and educators involved in organic chemistry and reaction stoichiometry will benefit from this discussion.

IBY
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Homework Statement



Okay, a while ago, I did a lab that had me get glucose osazone (C18-H22-N4-O4). Now, I am trying to calculate the theoretical mass of the osazone. The chemical equations goes as follows:

C6-H5-N2-H3*HCl + Na-C2-H3-O2*H2-O ------> C6-H5-N2-H3 + H-C2-H3-O2 + Na-Cl + 3(H2-O)

After that:
C6-H12-O6 + 3(C6-H5-N2-H3) --------> C18-H22-N4-O4 + C6-H5-N-H2 + N-H3 + 2(H2-O)

I found the limiting reactants in the first equation for Phenylhydrazine (C6-H5-N2-H3), but the thing is, in the second equation, 2 mols of phenylhydrazine gets used for osazone (C18-H22-N4-O4) and water, and the third mole decomposes into the ammonia (N-H3) and aniline (C6-H5-N-H2). So the part I am having trouble is, should I use the ration 2:1 from phenylhydrazine to osazone or keep the 3:1 ration in order to find the theoretical yield?
 
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IBY said:

Homework Statement



Okay, a while ago, I did a lab that had me get glucose osazone (C18-H22-N4-O4). Now, I am trying to calculate the theoretical mass of the osazone. The chemical equations goes as follows:

C6-H5-N2-H3*HCl + Na-C2-H3-O2*H2-O ------> C6-H5-N2-H3 + H-C2-H3-O2 + Na-Cl + 3(H2-O)

After that:
C6-H12-O6 + 3(C6-H5-N2-H3) --------> C18-H22-N4-O4 + C6-H5-N-H2 + N-H3 + 2(H2-O)

I found the limiting reactants in the first equation for Phenylhydrazine (C6-H5-N2-H3), but the thing is, in the second equation, 2 mols of phenylhydrazine gets used for osazone (C18-H22-N4-O4) and water, and the third mole decomposes into the ammonia (N-H3) and aniline (C6-H5-N-H2). So the part I am having trouble is, should I use the ration 2:1 from phenylhydrazine to osazone or keep the 3:1 ration in order to find the theoretical yield?

If instead of making the phenylhydrazine you used, you obtained it from a bottle... which ratio would you use?

Remember that the first reaction is essentially a neutralization reaction... the phenylhydrazine hydrochloride is free-based with sodium acetate. If I discover a way to do this that requires 20 moles of the the hydrochloride to my newly-discovered base (capable of neutralizing 20 moles of the hydrochloride!), will we all have to go back and rewrite every paper ever published that used sodium acetate for the job?
 

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