Classical Poissonian Process: Time-Dependent ω

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SUMMARY

The classical Poissonian process describes the probability of an event occurring in a time interval dt as ωdt. The probability that the event has not decayed by time t is given by P(t) = exp(-ωt), derived from a differential equation. When ω is time-dependent, the probability function modifies to P(t) = exp(-∫₀ᵗ ω(u) du), requiring the solution of the differential equation P'(t) = -ω(t)P(t). This adjustment highlights the impact of varying rates on decay probabilities.

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I think the classical Poissonian process is where you have something, which in a time dt has a probability ωdt. Then one can show quite easily that the probability that the "something" has not yet decayed goes as P(t)=exp(-ωt), because it obeys a differential equation with the given solution.
However, what does P(t) look like if ω is time dependent?
 
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Just like before, you have to solve the differential equation [itex]P'(t) = -\omega(t)P(t)[/itex]. The general solution is [itex]P(t) = \exp\left(-\int_0^t \omega(u)\,du\right).[/itex]
 

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