Classifying Equation 1: Linear, Semilinear or Quasilinear?

  • Context: MHB 
  • Thread starter Thread starter Julio1
  • Start date Start date
Click For Summary
SUMMARY

The equation $u_{x_1}+u_{x_2}=u^{3/2}$ is classified as quasi-linear based on its structure. It cannot be classified as linear due to the non-linear term $u^{3/2}$, which prevents it from fitting the linear form $a(x_1,x_2) \, \frac{\partial u}{\partial x_1}+b(x_1,x_2) \, \frac{\partial u}{\partial x_2}+c(x_1,x_2) \, u=d(x_1,x_2)$. The equation also does not meet the criteria for semilinearity, as the principal part is not linear. Therefore, the final classification is that the equation is quasi-linear.

PREREQUISITES
  • Understanding of first-order partial differential equations (PDEs)
  • Familiarity with linear, semilinear, and quasi-linear classifications
  • Knowledge of the notation for partial derivatives
  • Ability to manipulate and analyze mathematical equations
NEXT STEPS
  • Study the definitions and characteristics of linear, semilinear, and quasi-linear PDEs
  • Learn how to transform PDEs into standard forms for classification
  • Explore examples of quasi-linear equations and their solutions
  • Investigate the implications of non-linear terms in PDEs
USEFUL FOR

Mathematicians, students studying differential equations, and researchers in applied mathematics who are interested in the classification and analysis of partial differential equations.

Julio1
Messages
66
Reaction score
0
Classify the equation $u_{x_1}+u_{x_2}=u^{3/2}$ depending on if is linear, semilinear or quasilinear.

Hello MathHelpBoards :). The equation isn't linear? How prove this?
 
Physics news on Phys.org
Well, for a first-order pde in one dependent variable and two independent variables to be linear, you have to be able to write it as follows:
$$a(x_1,x_2) \, \frac{\partial u(x_1,x_2)}{\partial x_1}+b(x_1,x_2) \, \frac{\partial u(x_1,x_2)}{\partial x_2}+c(x_1,x_2) \, u(x_1,x_2)=d(x_1,x_2).$$
The RHS, being what it is, precludes being able to write it like this. Now the quasi-linear criteria is that you can write it like this:
$$a(x_1,x_2,u(x_1,x_2)) \, \frac{\partial u(x_1,x_2)}{\partial x_1}+b(x_1,x_2,u(x_1,x_2)) \, \frac{\partial u(x_1,x_2)}{\partial x_2}=c(x_1,x_2,u(x_1,x_2)).$$
Can you write your pde in this form?
 
Hello Ackbach :). I have clear that isn't linear, because the term $u^{3/2}$ isn't of first grade. Is this the explained?

But I don't how show that the equation is or not semilinear or quasi-linear. Can any help me please?
 
How about $a=b=1$, and then $c$ would have to equal...?
 
OK, then the equation is linear, because the operators $u_x$ and $u_y$ are linear. Therefore the equation isn't semilinear, because the equation is linear. Is quasilinear, because have the form for the definition.

This is right? :)
 
I would agree that the equation is quasi-linear. Your first sentence contradicts your latter sentences! Just because the operators on the LHS are linear (which is true) doesn't mean the equation is linear!
 
Ackbach said:
I would agree that the equation is quasi-linear. Your first sentence contradicts your latter sentences! Just because the operators on the LHS are linear (which is true) doesn't mean the equation is linear!

Thanks! Sorry, is a mistake.

The equation is quasi-linear because have the form for the definition, have that $c=u^{3/2}=(u(x_1,x_2))^{3/2}.$

The equation is linear because have the form:

$\dfrac{\partial u}{\partial x_1}(x_1,x_2)+\dfrac{\partial u}{\partial x_2}(x_1,x_2)+(-1)u^{3/2}=0$ where $a=b=1, c=-1.$

The equation isn't semilinear, because haven't principal part linear :).

I correct now?
 
Yep, looks good to me!
 
Thanks Ackbach :)!
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 36 ·
2
Replies
36
Views
8K
  • · Replies 4 ·
Replies
4
Views
1K