Collision between mass m and 2m at 45 degree deflection

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Physics Help! Pleaase

Homework Statement



A mass, m, traveling at a speed v, strikes another mass = 2m at rest. After the collision, the first mass, m, is delfected through 45 degrees and has a final speed of v/2.
Find the speed and Direction of the mass 2m after this collision.

Homework Equations


p =mv



The Attempt at a Solution



2mfsinT = -mv/2sin 45
mv+2m+ 0 - mv xdr
mv = mv/2cos45+2mfcosT

Anyone help ..
 
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I'm guessing you are trying to use conservation of momentum. What is f? What is xdr? Why do you only have a 2m there in the second line? Actually, that second line isn't even an equation! You need to start by drawing a diagram and breaking it up into x and y components, before the collision and after.
 
hage567 said:
I'm guessing you are trying to use conservation of momentum. What is f? What is xdr? Why do you only have a 2m there in the second line? Actually, that second line isn't even an equation! You need to start by drawing a diagram and breaking it up into x and y components, before the collision and after.

I have
let theta of missing angle = x
v2 = velocity of second mass , 2m
cos45mv/2 + cosX = mv
sin45mv/w= sin X 2Mv2
I can't solve it now..
 
"cos45mv/2 + cosX = mv"

There should be a term for the velocity of the 2m mass in front of the cosX.

"sin45mv/w= sin X 2Mv2"

I'm assuming the w is really a 2??

Everything looks OK I think. You have two equations and two unknowns (not counting the v that is the initial velocity). So put the second equation in terms of one of the unknowns and plug it into the first equation. Solve for that unknown.