Concentration problem using absorbance

[Rujano]

Homework Statement

Hi. A patient produced 1122 mL of urine in 24 hours.
A 1.00-mL aliquot of the sample was treated with
Mo(Vl) and ascorbic acid and was diluted to a
volume of 50.00 mL. A calibration curve was pre-
pared by treating 1.00-mL aliquots of phosphate
standard solutions in the same manner as the urine
sample. The absorbances of the standards and the
urine sample were obtained at 650 nm, and then
concentration of 1.00ml diluted aliquots of phosphate is found 2.5ppm.

What mass in grams of phosphorus was eliminated per day by the patient?

What is the concentration of phosphate in the urine (mmol/L)?

Homework Equations

A = abC

The Attempt at a Solution

Ok, what I really don't get is why in the first question they ask me for PHOSPHOROUS and in the second one for PHOSPHATE. And again, in the problem it says that this is a method used to determine PHOSPHOROUS, yet the standards are made of PHOSPHATE.

It's really confusing to me... they shouldn't be the same thing, right?

 

[mfb]

Phosphate contains phosphorus - one atom per molecule.