Contact force between two blocks with different friction coefficients

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devilish_wit
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Homework Statement


Two blocks of masses m1 and m2 are placed on a table in contact with each other as shown in the figure below. The coefficient of kinetic friction between the block of mass m1 and the table is μ1, and that between the block of mass m2 and the table is μ2. A horizontal force of magnitude F is applied to the block of mass m1. We wish to find P, the magnitude of the contact force between the blocks.
Diagram of two blocks on a horizontal table: block of mass m1 on the left, block of mass m2 on the right in contact with it, with a horizontal force F pointing right applied to m1.

Homework Equations



F = ma
Kinetic force = μk x FN

The Attempt at a Solution



I was pretty sure my answer for (d) was right. I'm not sure what I did wrong[/B]

Three answer-check parts from a physics problem: (b) net force on the two-block system, F - (μ1m1 + μ2m2)g, marked correct; (c) net force on m1, F - μ1m1g - P, marked correct; (d) net force on m2, F - μ2m2g + P, marked incorrect.
 
Attachments
  • Four answer fields for a physics problem with parts (a) to (d) at t = 0, 0.5 s, 1.1 s and 1.6 s; entries 721.08, 748.81 and 712.46 N are marked correct, while 3649.54 is marked incorrect with an error message.
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  • Three answer-check parts from a physics problem: (b) net force on the two-block system, F - (μ1m1 + μ2m2)g, marked correct; (c) net force on m1, F - μ1m1g - P, marked correct; (d) net force on m2, F - μ2m2g + P, marked incorrect.
    upload_2018-10-8_19-6-37.png
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  • Diagram of two blocks on a horizontal table: block of mass m1 on the left, block of mass m2 on the right in contact with it, with a horizontal force F pointing right applied to m1.
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Draw a free-body diagram for ##m_2##. What forces are directly acting on ##m_2##?
 
devilish_wit said:
I was pretty sure my answer for (d) was right. I'm not sure what I did wrong
You would have to tell us what you did before we can tell you what you did wrong. Can you tell us what you were thinking when you were "pretty sure" you'd done it correctly?

Note, by the way, that ##P## is an internal force.
 
Mister T said:
Note, by the way, that ##P## is an internal force.
Whether a force is "internal", "external", or irrelevant depends on where you have drawn the boundaries around the system of interest. For question d, I would draw the boundaries such that P is an external force.
 
Mister T said:
You would have to tell us what you did before we can tell you what you did wrong. Can you tell us what you were thinking when you were "pretty sure" you'd done it correctly?

Note, by the way, that ##P## is an internal force.

Two free-body diagrams drawn by hand. Left, labelled m1: arrows for N1 up, Fg = m1g down, F to the right, P 2 on 1 to the left, and fk 1 to the left. Right, labelled m2: arrows for N2 up, Fg = m2g down, P 1 on 2 to the right, and fk 2 to the left.


That's my free body diagram

For m1:

Fnet = F - P - μ1(N) ---> F - (μ1m1)g - P

For m2: (I'm not sure if F is still included in this equation or not?)

Fnet = F + P - μ2(N) ---> F - (μ2m2)g + P (this answer was wrong)
 
Attachments
  • Two free-body diagrams drawn by hand. Left, labelled m1: arrows for N1 up, Fg = m1g down, F to the right, P 2 on 1 to the left, and fk 1 to the left. Right, labelled m2: arrows for N2 up, Fg = m2g down, P 1 on 2 to the right, and fk 2 to the left.
    upload_2018-10-8_21-30-31.png
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jbriggs444 said:
Whether a force is "internal", "external", or irrelevant depends on where you have drawn the boundaries around the system of interest. For question d, I would draw the boundaries such that P is an external force.

Is my free body diagram correct?
Free-body diagram with two side-by-side force diagrams: m1 on the left, showing N1 up, Fg = m1g down, F right, P 2 on 1 left, and fk 1 left; m2 on the right, showing N2 up, Fg = m2g down, P 1 on 2 right, and fk 2 left.
 
Attachments
  • Free-body diagram with two side-by-side force diagrams: m1 on the left, showing N1 up, Fg = m1g down, F right, P 2 on 1 left, and fk 1 left; m2 on the right, showing N2 up, Fg = m2g down, P 1 on 2 right, and fk 2 left.
    upload_2018-10-8_21-30-31-png.png
    6.4 KB · Views: 1,131
devilish_wit said:
Is my free body diagram correct?
Yes, that looks correct.