Could someone Please help with DIMENSIONLESS VARIABLES.

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SUMMARY

The discussion focuses on transforming a heat conduction equation into dimensionless form. The original equation, k(d²T/dx² + Q) = 0, is modified by defining dimensionless variables, specifically 0 = x/b and z = (T - T(0))/(Qb²/K). This leads to the simplified equation d²z/d0² + 1 = 0, where the term '1' arises from the normalization of the equation after dividing by Q. The final dimensionless equation is d²z/ds² + 1 = 0, applicable for s in the range [-1, 1].

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juice34
My professor yields this equation. d^2z/d0^2+1=0. This problem has to do with heat conduction. So a plane sheet -b<=x<=+b with a constant heat source Q. The equation that needs to be solved is k(d2T/dx2+Q=0. To change this equation to dimensionless, therefore let's say 0=x/b and z=(T-T(0))/(Qb^2/K). This gives d2z/d0^2+1=0. I don't not understand where the 1 comes from can someone explain?
 
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Its a bit unfortunate to use O as a variable symbol. Btw, there is a parenthesis error in your expression k(d2T/dx2+Q=0. I'll assume k is only multiplying the derivative.

Anyway, I'd define s := x/b, so its domain is [-1,1].

The equation then becomes

k/(Qb^2) * d2T(bs)/ds2 + 1=0

where I have divided the whole equation by Q. Then define

z(s) := k/(Qb^2) * T(bs)

You then end up with

d^2z/ds^2+1=0

for s in [-1,1]. The boundary condition on z is obtained from the boundary condition on T, of course.

Torquil
 

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